printf（“％cx”，FILE2CHAR（F（fr）））到cout [关闭](printf(“%cx”, FILE2CHAR(F(fr))) to cout [closed])

printf（“％cx”，FILE2CHAR（F（fr）））到cout [关闭](printf(“%cx”, FILE2CHAR(F(fr))) to cout [closed])

如何用“cout”表达printf("%cx", FILE2CHAR(F(fr))) ？ （注意：FILE2CHAR（F（fr））返回一个int`）

我试过cout<<hex<<FILE2CHAR(F(fr)); 但在某些情况下，它仍然让我错误的十六进制。

我的错。 FILE2CHAR（F（fr））不返回int。 F（fr）返回一个int

FILE2CHAR是一个宏：

#define FILE2CHAR(f) ('a'+(f)) /* file to text */

谢谢

你打算打印什么？ ％cx将打印一个字符，后跟x。 为什么还要使用六角机械手呢？ - parkydr 因为我认为x指的是十六进制，我说对了吗？ 有点混淆这里的语法。

How can i express printf("%cx", FILE2CHAR(F(fr))) with "cout"? (Note: FILE2CHAR(F(fr)) returns a int`)

I have tried cout<<hex<<FILE2CHAR(F(fr)); but which in some cases, it still returns me wrong hex.

My mistake. FILE2CHAR(F(fr)) does not return a int. F(fr) returns a int

FILE2CHAR is a Macro:

#define FILE2CHAR(f) ('a'+(f)) /* file to text */

Thanks

What are you trying to print? %cx will print a character followed by x. Why use the hex manipulator anyway? – parkydr Because I thought x refers to hex, am I right? Kind of confused with the syntax here.

最满意答案

仍然有点困惑，所以我将涵盖这两种情况。

要打印字符，printf应该是

printf("%c", FILE2CHAR(F(fr)));

流等价物是

cout << static_cast<char>(FILE2CHAR(F(fr)));

强制转换是必需的，因为FILE2CHAR将返回一个整数，因此cout将显示整数值。

要打印十六进制值，printf应该是

printf("%x", FILE2CHAR(F(fr)));

流等价物是

cout << hex << FILE2CHAR(F(fr));

注意：在您使用dec操纵器之前，所有后续数字都将以十六进制显示。

Still a bit confused so I'll cover both situations.

To print a character, the printf should be

printf("%c", FILE2CHAR(F(fr)));

The stream equivalent is

cout << static_cast<char>(FILE2CHAR(F(fr)));

The cast is required because FILE2CHAR will return an integer so cout would display the integer value.

To print the hex value, the printf should be

printf("%x", FILE2CHAR(F(fr)));

The stream equivalent is

cout << hex << FILE2CHAR(F(fr));

Note: all subsequent numbers will be displayed in hex until you use the dec manipulator.