我的python项目路径/project 及其这些文件:
My python project path /project and these are its files :
/project/test.py /project/templates/ /project/includes/ /project/includes/config.py # config.py import os template_path = os.path.join(os.path.dirname(__file__), "templates")当我使用execute()函数从test.py包含config.py时,执行/project/includes/config.php 文件并将结果返回到/project/includes/test.py ,因此template_path变量已另存为/project/includes/templates/,而在此找不到模板文件夹.我想要一个函数包含/project/test.py 中的/project/includes/config.py 并在/project/includes/config中执行所有功能.py 到 test.py .
when I used execute() function to include config.py from test.py , the /project/includes/config.php file was executed and the result was returned to /project/includes/test.py so template_path variable was saved as /project/includes/templates/ and templates folder would not be found there . I want a function to include /project/includes/config.py from /project/test.py and execute all functions in /project/includes/config.py through test.py.
推荐答案在 includes 中创建一个(空)文件 __ init __.py .
Create a (empty) file __init__.py in includes.
在 test.py 中,通过执行 import 调用 config.py .
from包含导入配置
因此,如果在 config 中有一个说 foo 的函数,则您将这样称呼它:
So if there is a function say foo in config, you will call it like:
config.foo()
请参阅文档(如 MYYN )
更多推荐
有没有替代Python的函数,如PHP include()函数?
发布评论