什么是确定排序的最Python方式？(What's the most Pythonic way of determining endianness?)

什么是确定排序的最Python方式？(What's the most Pythonic way of determining endianness?)

我试图找出计算我的代码运行的机器是大端还是小端的最佳方法。 我有一个可行的解决方案（虽然我没有在大型机器上测试过），但看起来有点笨拙：

import struct little_endian = (struct.pack('@h', 1) == struct.pack('<h', 1))

这只是比较“本地”双字节包和小端包。 有更漂亮的方法吗？

I'm trying to find the best way of working out whether the machine my code is running on is big-endian or little-endian. I have a solution that works (although I haven't tested it on a big-endian machine) but it seems a bit clunky:

import struct little_endian = (struct.pack('@h', 1) == struct.pack('<h', 1))

This is just comparing a 'native' two-byte pack to a little-endian pack. Is there a prettier way?

最满意答案

答案在sys模块中 ：

>>> import sys >>> sys.byteorder 'little'

当然，根据你的机器，它可能会返回'big' 。 你的方法当然也应该工作。

The answer is in the sys module:

>>> import sys >>> sys.byteorder 'little'

Of course depending on your machine it may return 'big'. Your method should certainly work too though.