如何在迭代它时将列表拆分为两个并使用LINQ将结果放在元组中？(How to split a list in two while iterating over it and place the res

如何在迭代它时将列表拆分为两个并使用LINQ将结果放在元组中？(How to split a list in two while iterating over it and place the results in a tuple using LINQ?)

如果我有一个可枚举的话是否可能

Input :[1,2,3,4] Output :([1,3],[2,4])

迭代一次并开始将奇数放在序列/列表/中，甚至在另一个中，最后将两个序列放在一个元组中？

我尝试过类似的东西：

class Elem { int x; } (rez1,rez2)=from value in Generator() let odds=Enumerable.Empty<Elem>() let evens=Enumerable.Empty<Elem>() select(value%2==0?odds.**append**(value):odds.**append**(value))

我如何指导元组的一个元素的选择或每个元素的另一个元素？我可以在linq查询中有两个可变列表吗？

PS我试图实现类似的东西（类似于Haskell）：

select element -> predicate True -> goes to first element of result tuple predicate False-> goes to second element of result tuple

一切都在0（n）

Is it possible if i have an enumerable

Input :[1,2,3,4] Output :([1,3],[2,4])

to iterate once over it and start putting odd numbers in a sequence/list/whatever and even in another and at the end placing the two sequences in a tuple?

I have tried something like:

class Elem { int x; } (rez1,rez2)=from value in Generator() let odds=Enumerable.Empty<Elem>() let evens=Enumerable.Empty<Elem>() select(value%2==0?odds.**append**(value):odds.**append**(value))

How can i direct the select over one element of the tuple or the other for each element?Can i have two mutable lists inside a linq query?

P.S I am trying to achieve something like (similar to Haskell) :

select element -> predicate True -> goes to first element of result tuple predicate False-> goes to second element of result tuple

Everything in 0(n)

最满意答案

创建如下的元组。 对奇数和偶数值运行两个查询。

Tuple.Create(input.Where(c => c % 2 == 1).ToArray(), input.Where(c => c % 2 == 0).ToArray());

Create tuple like the following. Run two queries for odd and even values.

Tuple.Create(input.Where(c => c % 2 == 1).ToArray(), input.Where(c => c % 2 == 0).ToArray());