如何绘制宽度不等的直方图而不用原始数据计算？(How to plot a histogram with unequal widths without computing it from raw dat

如何绘制宽度不等的直方图而不用原始数据计算？(How to plot a histogram with unequal widths without computing it from raw data?)

Matplotlib的hist表示“计算并绘制x的直方图”。 我想制作一个没有先计算任何东西的情节。 我有bin宽度（不相等），以及每个bin中的总量，我想绘制一个频率 - 数量直方图。

例如，有了数据

cm Frequency 65-75 2 75-80 7 80-90 21 90-105 15 105-110 12

它应该是这样的情节：

http://www.gcsemathstutor.com/histograms.php

块的面积代表每个类的频率。

Matplotlib's hist says "Compute and draw the histogram of x". I'd like to make a plot without computing anything first. I have the bin widths (unequal), and the total amount in each bin, and I want to plot a frequency-quantity histogram.

For instance, with the data

cm Frequency 65-75 2 75-80 7 80-90 21 90-105 15 105-110 12

It should make a plot like this:

http://www.gcsemathstutor.com/histograms.php

where the area of the blocks represents the frequency in each class.

最满意答案

像David Zwicker一样工作：

import numpy as np import matplotlib.pyplot as plt freqs = np.array([2, 7, 21, 15, 12]) bins = np.array([65, 75, 80, 90, 105, 110]) widths = bins[1:] - bins[:-1] heights = freqs.astype(np.float)/widths plt.fill_between(bins.repeat(2)[1:-1], heights.repeat(2), facecolor='steelblue') plt.show()

Working on the same as David Zwicker:

import numpy as np import matplotlib.pyplot as plt freqs = np.array([2, 7, 21, 15, 12]) bins = np.array([65, 75, 80, 90, 105, 110]) widths = bins[1:] - bins[:-1] heights = freqs.astype(np.float)/widths plt.fill_between(bins.repeat(2)[1:-1], heights.repeat(2), facecolor='steelblue') plt.show()