本文介绍了在分配之前使用变量“test" - Typescript的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
限时送ChatGPT账号..我在执行打字稿代码时遇到错误.我在这里将一种类型映射到另一种类型.但是 vscode 显示在分配之前使用了变量test"的错误.有人可以帮忙吗?
I am getting error in this implementation of typescript code. I am mapping here one type to another. But vscode shows error that variable 'test' is used before being assigned. can anyone please help?
interface A {
name: string;
age: string;
sex: string;
}
interface B {
name: any;
age: string;
sex: string;
}
const modifyData = (g : B) :A => {
let test: A;
test.name = g.name['ru'];
test.age = g.age;
test.sex = g.sex;
return test as A;
};
const g = [{
"name": {
"en": "George",
"ru": "Gregor"
},
"age": "21",
"sex": "Male"
},
{
"name": {
"en": "David",
"ru": "Diva"
},,
"age": "31",
"sex": "Male"
}];
const data = g.map(modifyData);
console.log(data);
推荐答案
确实是未分配的.它被定义了,但它没有价值.
It is indeed unassigned. It is defined, but it has no value.
在我看来,最简洁的方法是返回一个字面量:
In my humble opinion, the cleanest way would be to return a literal:
const modifyData = (g: B):A => {
return {
name: g.name['ru'],
age: g.age,
sex: g.sex
} as A;
};
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