本文介绍了如何从计算属性名称的函数参数中获取文字类型?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
限时送ChatGPT账号..请考虑以下代码:
const fn = (name: string) => {
return { [name]: "some txt" };
};
const res = fn("books"); // books or any other string
TS 将 res
识别为以下类型:
TS recognizes res
as the following type:
const res: {
[x: string]: string;
}
我想让 TS 知道 res
有一个属性 books
I'd like TS to know that res
has a property books
const res: {
books: string;
}
我尝试了很多东西,但似乎没有任何效果.有可能吗?这是一个已知问题吗?
I tried many things but nothing seems to work. Is it possible at all? Is it a known issue?
推荐答案
你必须像这样创建一个泛型函数:
You have to create a generic function like this:
const fn = <T extends string>(name: T): { [key in T]: string } => {
return { [name]: "some txt" } as any;
};
const res = fn("books");
这似乎是 TypeScript 中的一个错误,它不允许这样的事情,这就是为什么你需要 as any
.请参阅此处交互示例
It seems like a bug in TypeScript that it doesn't allow such things, that's why you need the as any
. See here for an interactive example.
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