问题描述
限时送ChatGPT账号..我想输入一个数组,其中第一个元素始终是数字,其余元素始终是字符串,并且长度至少为 1.
I want to type an array where the first element is always a number, and the rest of the elements are always strings, and the length as to be at least 1.
这是我最大的努力:
type MyArray =
| [number]
| [number, string]
| [number, string, string]
| [number, string, string, string];
我如何让它永远持续下去?
How do I make that go on forever?
推荐答案
在 TypeScript 3.0 之前,真的没有什么比您拥有的联合更好的了.但是随后引入了一系列相关的新功能以更好地支持元组类型,特别是它们与函数参数列表的关系.由于函数支持最终的 rest 参数将不确定数量的参数的类型表示为数组,引入最终的 元组中的其余元素 将无限数量的元组元素的类型表示为数组.
Before TypeScript 3.0 there really wasn't anything better than a union like you have. But then a bunch of related new features were introduced to better support tuple types, and specifically their relationship to lists of function parameters. And since functions support a final rest parameter representing the type of an indefinite number of parameters as an array, it made sense to introduce a final rest element in a tuple representing the type of an indefinite number of tuple elements as an array.
嘿,事实上,您的用例在文档中作为示例明确提及:
Hey, in fact, your use case is explicitly mentioned as an example in the documentation:
例如,[number, ...string[]]
表示具有 number
元素后跟任意数量的 string
元素的元组.
For example,
[number, ...string[]]
means tuples with anumber
element followed by any number ofstring
elements.
那么让我们尝试一下:
type MyArray = [number, ...string[]];
const okay0: MyArray = [0]; // okay
const okay1: MyArray = [1, "a"]; // okay
const okay2: MyArray = [2, "a", "b"]; // okay
const okay3: MyArray = [3, "a", "b", "c", "d", "e", "f", "g", "h", "i", "j"]; // okay
const bad0: MyArray = [0, "a", false]; // error!
// ~~~~ <-- boolean is not assignable to string
const bad1: MyArray = ["x", "y"]; // error!
// ~~~ <-- string is not assignable to number
const bad2: MyArray = []; // error!
// ~~~~ <--- property '0' is missing (i.e., bad2[0] is missing)
我觉得不错.希望有所帮助;祝你好运!
Looks good to me. Hope that helps; good luck!
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