如何在C＃中编写代码

本文介绍了如何在C＃中编写代码的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

大家好， 我有一个必须满足以下三个条件的要求 1一个或多个2 ----只保留一个2，放下休息 Ex：2,2,2,2 - > 2 2.一个或多个3 ----只保留一个3，放下休息 Ex：3,3,3， 3 - > 3 3.一个或多个2 +一个或多个3 .....只保留2个，放弃其余 例如：2,2,3,3,3,3 - > 2. 请帮我编写符合上述所有条件的c＃代码。 谢谢。 我尝试了什么： if（count of 2） ）> 1 保留前2并删除休息 if（count of 3）> 1 保留前3并删除休息 第3个条件？

解决方案

if（count of 2）> 0 保留前2并删除休息 if（count of 3）> 0 保留前3并删除休息 if（2> 0 &&计数3> 0） 保留前2并删除休息

问题没有正确制定，配方不是从一开始就开始的。 这是个主意：如果input是一个数组，您需要了解在初始化后不能从数组中删除任何元素。因此，您必须创建一个全新的数组对象并将其返回。对于每种情况，您可以计算输出数组中需要多少个数组元素，并使用此长度初始化一个新数组。然后将元素从输入数组复制到输出数组，但是，根据具体情况，不是全部。

-SA

Hi all, I have a required which should satisfy all three conditions below 1. one or more 2 ---- keep only one 2, drop rest Ex : 2,2,2,2 - > 2 2. one or more 3----keep only one 3, drop rest Ex: 3,3,3,3 -> 3 3. one or more 2 + one or more 3 .....keep only 2, drop the rest Ex : 2,2,3,3,3,3 -> 2. Please help me in writing c # code which satisfies all above conditions. Thank you. What I have tried: if (count of 2) > 1 retain first 2 and delete rest if(count of 3) > 1 retain first 3 and delete rest 3rd condition?

解决方案

if (count of 2) > 0 retain first 2 and delete rest if(count of 3) > 0 retain first 3 and delete rest if (count of 2 > 0 && count of 3 > 0) retain first 2 and delete rest

The question is not correctly formulated, the formulation is not started from the beginning. Here is the idea: if input is an array, you need to understand that you cannot delete any elements from the array after it is initialized. Therefore, you would have to create a brand new array object and return it. For each case, you count how many array elements you need in an output array and initialize a new array with this length. Then you copy elements from the input array to the output array, but, depending on the case, not all of them.

—SA