iOS Swift:呈现imagePicker后SlidingMenuView位置错误

本文介绍了iOS Swift:呈现imagePicker后SlidingMenuView位置错误的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

限时送ChatGPT账号..

我在 TabBar 控制器和导航控制器的项目中使用 PageMenu.当我初始化滚动菜单"时，我使用它在状态栏和导航栏下显示它:

I am using PageMenu in my project within a TabBar Controller and a Navigation Controller. When I initialize the "Scrolling menu" I use this to display it under the statusBar and the navigation bar :

pageMenu = CAPSPageMenu(viewControllers: controllerArray, frame: CGRectMake(0, UIApplication.sharedApplication().statusBarFrame.size.height + self.navigationController!.navigationBar.frame.height, self.view.frame.width, self.view.frame.height), options: parameters)

此解决方案运行良好，可在我想要的位置准确显示我的菜单！然后我在其中一个滚动视图中呈现一个图像选择器视图.关闭后，菜单回到初始位置(导航栏下)...

This solution is working perfectly and display my menu exactly where I want ! Then I present an image picker view inside one of the scrolling view. After dismissing it, the menu goes back to the initial place (under the navigation bar)...

有什么解决方案可以避免这个问题?(如果您需要更多详细信息，我可以提供更多代码)

Any solution to avoid this issue ? (If you need more detail I can provide more code)

附言我的母语不是英语，所以我希望我的问题可以理解:)

P.S. I'm not a native English speaker so I hope my question is understandable :)

推荐答案

添加viewcontrollerpageMenu"作为父控制器的子级，问题解决

Added the viewcontroller "pageMenu" as a child of the parent controller and the problem was solved

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