使用Python 2在XML中按属性查找所有节点(Find all nodes by attribute in XML using Python 2)

使用Python 2在XML中按属性查找所有节点(Find all nodes by attribute in XML using Python 2)

我有一个XML文件，它具有许多具有相同属性的不同节点。

我想知道是否有可能使用Python和任何其他包如minidom或ElementTree来查找所有这些节点。

I have an XML file which has a lot of different nodes with the same attribute.

I was wondering if it's possible to find all these nodes using Python and any additional package like minidom or ElementTree.

最满意答案

您可以使用内置的xml.etree.ElementTree模块。

如果您希望所有具有特定属性的元素（无论属性值如何），则可以使用xpath表达式 ：

//tag[@attr]

或者，如果你关心价值：

//tag[@attr="value"]

示例（使用findall()方法 ）：

import xml.etree.ElementTree as ET data = """ <parent> <child attr="test">1</child> <child attr="something else">2</child> <child other_attr="other">3</child> <child>4</child> <child attr="test">5</child> </parent> """ parent = ET.fromstring(data) print [child.text for child in parent.findall('.//child[@attr]')] print [child.text for child in parent.findall('.//child[@attr="test"]')]

打印：

['1', '2', '5'] ['1', '5']

You can use built-in xml.etree.ElementTree module.

If you want all elements that have a particular attribute regardless of the attribute values, you can use an xpath expression:

//tag[@attr]

Or, if you care about values:

//tag[@attr="value"]

Example (using findall() method):

import xml.etree.ElementTree as ET data = """ <parent> <child attr="test">1</child> <child attr="something else">2</child> <child other_attr="other">3</child> <child>4</child> <child attr="test">5</child> </parent> """ parent = ET.fromstring(data) print [child.text for child in parent.findall('.//child[@attr]')] print [child.text for child in parent.findall('.//child[@attr="test"]')]

Prints:

['1', '2', '5'] ['1', '5']