如何自动生成N个“distinct"颜色?

本文介绍了如何自动生成N个“distinct"颜色?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我写了下面两个方法来自动选择N个不同的颜色.它的工作原理是在 RGB 立方体上定义分段线性函数.这样做的好处是，如果您想要的话，您还可以获得渐进式比例，但是当 N 变大时，颜色可能会开始看起来相似.我还可以想象将RGB立方体均匀地细分为一个点阵，然后绘制点.有谁知道其他方法吗?我排除了定义一个列表然后循环遍历它的可能性.我还应该说，我通常不在乎它们是否发生冲突或不好看，它们只需要在视觉上与众不同.

I wrote the two methods below to automatically select N distinct colors. It works by defining a piecewise linear function on the RGB cube. The benefit of this is you can also get a progressive scale if that's what you want, but when N gets large the colors can start to look similar. I can also imagine evenly subdividing the RGB cube into a lattice and then drawing points. Does anyone know any other methods? I'm ruling out defining a list and then just cycling through it. I should also say I don't generally care if they clash or don't look nice, they just have to be visually distinct.

public static List<Color> pick(int num) { List<Color> colors = new ArrayList<Color>(); if (num < 2) return colors; float dx = 1.0f / (float) (num - 1); for (int i = 0; i < num; i++) { colors.add(get(i * dx)); } return colors; } public static Color get(float x) { float r = 0.0f; float g = 0.0f; float b = 1.0f; if (x >= 0.0f && x < 0.2f) { x = x / 0.2f; r = 0.0f; g = x; b = 1.0f; } else if (x >= 0.2f && x < 0.4f) { x = (x - 0.2f) / 0.2f; r = 0.0f; g = 1.0f; b = 1.0f - x; } else if (x >= 0.4f && x < 0.6f) { x = (x - 0.4f) / 0.2f; r = x; g = 1.0f; b = 0.0f; } else if (x >= 0.6f && x < 0.8f) { x = (x - 0.6f) / 0.2f; r = 1.0f; g = 1.0f - x; b = 0.0f; } else if (x >= 0.8f && x <= 1.0f) { x = (x - 0.8f) / 0.2f; r = 1.0f; g = 0.0f; b = x; } return new Color(r, g, b); }

推荐答案

您可以使用 HSL 颜色模型 来创建你的颜色.

You can use the HSL color model to create your colors.

如果您只想要不同的色调(可能)，以及亮度或饱和度的细微变化，您可以像这样分配色调:

If all you want is differing hues (likely), and slight variations on lightness or saturation, you can distribute the hues like so:

// assumes hue [0, 360), saturation [0, 100), lightness [0, 100) for(i = 0; i < 360; i += 360 / num_colors) { HSLColor c; c.hue = i; c.saturation = 90 + randf() * 10; c.lightness = 50 + randf() * 10; addColor(c); }