问题描述
限时送ChatGPT账号..我在一个项目中使用 libmysql,每次在 Valgrind 中,我总是看到确切的泄漏摘要仍然可以访问:21 个块中的 73,944 字节",这不应该存在.后来我从这个链接一个>:
I was using libmysql in a project and I always see the exact leak summary 'still reachable: 73,944 bytes in 21 blocks' every time in Valgrind, which shouldn't be there. Later I tested this sample program from this link:
/* Simple C program that connects to MySQL Database server*/
#include <mysql.h>
#include <stdio.h>
main() {
MYSQL *conn;
MYSQL_RES *res;
MYSQL_ROW row;
char *server = "localhost";
char *user = "root";
char *password = "PASSWORD"; /* set me first */
char *database = "mysql";
conn = mysql_init(NULL);
/* Connect to database */
if (!mysql_real_connect(conn, server,
user, password, database, 0, NULL, 0)) {
fprintf(stderr, "%s\n", mysql_error(conn));
exit(1);
}
/* send SQL query */
if (mysql_query(conn, "show tables")) {
fprintf(stderr, "%s\n", mysql_error(conn));
exit(1);
}
res = mysql_use_result(conn);
/* output table name */
printf("MySQL Tables in mysql database:\n");
while ((row = mysql_fetch_row(res)) != NULL)
printf("%s \n", row[0]);
/* close connection */
mysql_free_result(res);
mysql_close(conn);
}
当我用 Valgrind 运行这个时,我仍然得到:
When I run this with Valgrind, I'm still getting:
==22556== LEAK SUMMARY:
==22556== definitely lost: 0 bytes in 0 blocks
==22556== indirectly lost: 0 bytes in 0 blocks
==22556== possibly lost: 0 bytes in 0 blocks
==22556== still reachable: 73,944 bytes in 21 blocks
==22556== suppressed: 0 bytes in 0 blocks
这是否值得担心?这是 libmysql 中的错误吗?
推荐答案
仍然可以访问"并不意味着存在问题.来自马嘴:
"Still reachable" doesn't mean that there is a problem. From the horse's mouth:
仍然可以访问"意味着你的程序可能没问题——它不是免费的它可能有一些记忆.这是很常见的,而且通常是合理的.如果您不想看到这些报告,请不要使用 --show-reachable=yes.
"still reachable" means your program is probably ok -- it didn't free some memory it could have. This is quite common and often reasonable. Don't use --show-reachable=yes if you don't want to see these reports.
这篇关于Valgrind:libmysql 示例程序给出“仍然可达:"泄漏的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
更多推荐
[db:关键词]
发布评论