我怎样才能通过他们的标题来对齐多个地块而不是地块面积？

本文介绍了我怎样才能通过他们的标题来对齐多个地块而不是地块面积？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我使用软件包

left_col < - cowplot :: plot_grid（p1 + ggtitle（），p2 + ggtitle（）， labels = c（'a）'， 'b）'），label_size = 14， ncol = 1，align ='v'，axis ='lr'） cowplot :: plot_grid（left_col，p3 + ggti tle（）， labels = c（''，'c）'），label_size = 14， align ='h'，axis ='b'）

请参阅还

I'm using egg package developed by @baptiste. Below is an example from github. I'm wondering if it's possible to align two columns by the titles a) and c) instead of plot area? Thanks!

Code:

library(egg) library(grid) p1 <- ggplot(mtcars, aes(mpg, wt, colour = factor(cyl))) + geom_point() + ggtitle("a)") p1 p2 <- ggplot(mtcars, aes(mpg, wt, colour = factor(cyl))) + geom_point() + facet_wrap(~ cyl, ncol = 2, scales = "free") + guides(colour = "none") + theme() + ggtitle("b)") p2 p3 <- ggplot(mtcars, aes(mpg, wt, colour = factor(cyl))) + geom_point() + facet_grid(. ~ am, scales = "free") + guides(colour="none") + ggtitle("c)") p3 g1 <- ggplotGrob(p1) g2 <- ggplotGrob(p2) g3 <- ggplotGrob(p3) fg1 <- gtable_frame(g1, debug = TRUE) fg2 <- gtable_frame(g2, debug = TRUE) fg12 <- gtable_frame(gtable_rbind(fg1, fg2), width = unit(2, "null"), height = unit(1, "null")) fg3 <- gtable_frame( g3, width = unit(2, "null"), height = unit(1, "null"), debug = TRUE ) grid.newpage() combined <- gtable_cbind(fg12, fg3) grid.draw(combined)

Plot:

解决方案

I found another way by using cowplot package

left_col <- cowplot::plot_grid(p1 + ggtitle(""), p2 + ggtitle(""), labels = c('a)', 'b)'), label_size = 14, ncol = 1, align = 'v', axis = 'lr') cowplot::plot_grid(left_col, p3 + ggtitle(""), labels = c('', 'c)'), label_size = 14, align = 'h', axis = 'b')

See also here

Edit:

A recently developed package patchwork for ggplot2 can also get the job done

library(patchwork) { p1 + {p2} + patchwork::plot_layout(ncol = 1) } / p3 + patchwork::plot_layout(ncol = 2)