本文介绍了如何使用openfiledialog控件将文件路径传递给变量?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
限时送ChatGPT账号..我在这里有这个代码,我用它来以 Windows 形式上传一些东西:
public Form1(){初始化组件();}private void btnLoad_Click(object sender, EventArgs e){OpenFileDialog ofd = new OpenFileDialog();System.Windows.Forms.DialogResult dr = ofd.ShowDialog();如果(博士 == DialogResult.OK){userSelectedFilePath = ofd.FileName;}}公共字符串 userSelectedFilePath{得到{ 返回 tbFilePath.Text;}放{tbFilePath.Text = value;}}private void btn_compare_Click(object sender, EventArgs e){字符串 Xml1 = tbFilePath.Text;string Xml2 = System.IO.File.ReadAllText(@"C:");compareparison(Xml1, Xml2);}
显然我做错了什么,因为我没有传递我需要的 tbFilePath.Text
:string Xml1 = tbFilePath.Text
;>
这是什么?
解决方案您可能想要的是比较 2 个文件的内容.
正如siride所说,您的代码没有意义(请参阅他的评论)
将此方法添加到您的类中
私有字符串 FindFile(){OpenFileDialog ofd = new OpenFileDialog();string _xmlPath1 = Environment.GetFolderPath(Environment.SpecialFolder.MyPictures);System.Windows.Forms.DialogResult dr = ofd.ShowDialog();如果(博士 == DialogResult.OK)返回 d.FileName;别的返回空;}
然后你可以这样做:
private void btn_compare_Click(object sender, EventArgs e){字符串 x1 = System.IO.File.ReadAllText(FindFile(), Encoding.UTF8);字符串 x2 = System.IO.File.ReadAllText(FindFile(), Encoding.UTF8);//或者如果你已经有了第二个文件//string x2 = System.IO.File.ReadAllText(@"C:\YourPath\someFileName.xml", Encoding.UTF8);compareparison(x1, x2);}
I have this code here which i use in order to upload some stuff in a windows form:
public Form1()
{
InitializeComponent();
}
private void btnLoad_Click(object sender, EventArgs e)
{
OpenFileDialog ofd = new OpenFileDialog();
System.Windows.Forms.DialogResult dr = ofd.ShowDialog();
if (dr == DialogResult.OK)
{
userSelectedFilePath = ofd.FileName;
}
}
public string userSelectedFilePath
{
get
{ return tbFilePath.Text;
}
set
{tbFilePath.Text = value;
}
}
private void btn_compare_Click(object sender, EventArgs e)
{
string Xml1 = tbFilePath.Text;
string Xml2 = System.IO.File.ReadAllText(@"C:");
compareparison(Xml1, Xml2);
}
Apparently i'm doing something wrong because i'm not passing the tbFilePath.Text
which i need when i have: string Xml1 = tbFilePath.Text
;
What is it?
解决方案What you probably want is to compare the contents of 2 files.
As siride said your code does not make sense(see his comment)
Add this method to your class
private string FindFile()
{
OpenFileDialog ofd = new OpenFileDialog();
string _xmlPath1 = Environment.GetFolderPath(Environment.SpecialFolder.MyPictures);
System.Windows.Forms.DialogResult dr = ofd.ShowDialog();
if (dr == DialogResult.OK)
return ofd.FileName;
else
return null;
}
And then you can do this:
private void btn_compare_Click(object sender, EventArgs e)
{
string x1 = System.IO.File.ReadAllText(FindFile(), Encoding.UTF8);
string x2 = System.IO.File.ReadAllText(FindFile(), Encoding.UTF8);
//Or if you already have the second file
//string x2 = System.IO.File.ReadAllText(@"C:\YourPath\someFileName.xml", Encoding.UTF8);
compareparison(x1, x2);
}
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