受启发的Lua程序在计算机和计算器上有所不同

本文介绍了受启发的Lua程序在计算机和计算器上有所不同的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在尝试为TI-Nspire CX CAS创建一个简单的二次公式程序.我似乎一切正确，并且可以在计算机上运行:

I am attempting to create a simple quadratic formula program for my TI-Nspire CX CAS. I seem to have everything correct, and it works on the computer:

但是，它在计算器上不起作用.我得到第二个正确的，但第一个是-4.44089 ... e-16. (不说...，只是使用它是因为我不想输入整个内容)

However, it doesn't work on the calculator. I get the second one correct, but the 1st is -4.44089...e-16. (doesn't say ..., just using it because I don't want to type out the whole thing)

(简化的)代码如下:

function quadraticA(f,s,t) return ((-1*s)+math.sqrt(s^2-4*f*t))/(2*f) end function quadraticB(f,s,t) return ((-1*s)-math.sqrt(s^2-4*f*t))/(2*f) end function on.paint(gc) formula:setExpression("0s: "..quadraticA(tonumber(a),tonumber(b),tonumber(c))) formulaB:setExpression(quadraticB(tonumber(a),tonumber(b),tonumber(c))) end

为什么在计算器上然后在计算机上得到不同的答案?我该如何解决该问题?

Why do I get a different answer on the calculator then on the computer? How can I fix the issue?

提前谢谢！

推荐答案

正如Dimitry所指出的，本质上，我必须编写一个CAS引擎.这是lua的平方根简化:

As Dimitry pointed out, I must write, essentially, a CAS engine. Here is a square root simplification in lua:

function factors(a) factorsOfA={} counter = 0 for i = 1, a do counter = counter + 1 if modulo(a,i) == 0 then factorsOfA[counter]=i end end return factorsOfA end function simplifySqrt(radicand) radicandFactors = factors(radicand) outsideRadicand = 1 for m,i in pairs(radicandFactors) do if math.floor(math.sqrt(i))^2 == i then outsideRadicand = outsideRadicand * math.floor(math.sqrt(i)) end end insideRadicand = radicand/outsideRadicand^2 return outsideRadicand.."sqrt("..insideRadicand..")" end

我希望这会有所帮助！