R中的和弦图

本文介绍了R中的和弦图的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

cran 中是否有任何包可以绘制这样的和弦布局:(此可视化也称为和弦图)

Is there any package in cran which could plot a chord layout like this: (this visualization is also called chord diagram)

推荐答案

我几年前写了以下内容，但从未真正使用过它:随意调整它以满足您的需求，甚至将其变成一个成熟的包.

I wrote the following several years ago, but never really used it: feel free to adapt it to your needs, or even turn it into a full-fledged package.

# Return a line in the Poincare disk, i.e., # a circle arc, perpendicular to the unit circle, through two given points. poincare_segment <- function(u1, u2, v1, v2) { # Check that the points are sufficiently different if( abs(u1-v1) < 1e-6 && abs(u2-v2) < 1e-6 ) return( list(x=c(u1,v1), y=c(u2,v2)) ) # Check that we are in the circle stopifnot( u1^2 + u2^2 - 1 <= 1e-6 ) stopifnot( v1^2 + v2^2 - 1 <= 1e-6 ) # Check it is not a diameter if( abs( u1*v2 - u2*v1 ) < 1e-6 ) return( list(x=c(u1,v1), y=c(u2,v2)) ) # Equation of the line: x^2 + y^2 + ax + by + 1 = 0 (circles orthogonal to the unit circle) a <- ( u2 * (v1^2+v2^2) - v2 * (u1^2+u2^2) + u2 - v2 ) / ( u1*v2 - u2*v1 ) b <- ( u1 * (v1^2+v2^2) - v1 * (u1^2+u2^2) + u1 - v1 ) / ( u2*v1 - u1*v2 ) # Swap 1's and 2's # Center and radius of the circle cx <- -a/2 cy <- -b/2 radius <- sqrt( (a^2+b^2)/4 - 1 ) # Which portion of the circle should we draw? theta1 <- atan2( u2-cy, u1-cx ) theta2 <- atan2( v2-cy, v1-cx ) if( theta2 - theta1 > pi ) theta2 <- theta2 - 2 * pi else if( theta2 - theta1 < - pi ) theta2 <- theta2 + 2 * pi theta <- seq( theta1, theta2, length=100 ) x <- cx + radius * cos( theta ) y <- cy + radius * sin( theta ) list( x=x, y=y ) } # Sample data n <- 10 m <- 7 segment_weight <- abs(rnorm(n)) segment_weight <- segment_weight / sum(segment_weight) d <- matrix(abs(rnorm(n*n)),nr=n, nc=n) diag(d) <- 0 # No loops allowed # The weighted graph comes from two quantitative variables d[1:m,1:m] <- 0 d[(m+1):n,(m+1):n] <- 0 ribbon_weight <- t(d) / apply(d,2,sum) # The sum of each row is 1; use as ribbon_weight[from,to] ribbon_order <- t(apply(d,2,function(...)sample(1:n))) # Each row contains sample(1:n); use as ribbon_order[from,i] segment_colour <- rainbow(n) segment_colour <- brewer.pal(n,"Set3") transparent_segment_colour <- rgb(t(col2rgb(segment_colour)/255),alpha=.5) ribbon_colour <- matrix(rainbow(n*n), nr=n, nc=n) # Not used, actually... ribbon_colour[1:m,(m+1):n] <- transparent_segment_colour[1:m] ribbon_colour[(m+1):n,1:m] <- t(ribbon_colour[1:m,(m+1):n]) # Plot gap <- .01 x <- c( segment_weight[1:m], gap, segment_weight[(m+1):n], gap ) x <- x / sum(x) x <- cumsum(x) segment_start <- c(0,x[1:m-1],x[(m+1):n]) segment_end <- c(x[1:m],x[(m+2):(n+1)]) start1 <- start2 <- end1 <- end2 <- ifelse(is.na(ribbon_weight),NA,NA) x <- 0 for (from in 1:n) { x <- segment_start[from] for (i in 1:n) { to <- ribbon_order[from,i] y <- x + ribbon_weight[from,to] * ( segment_end[from] - segment_start[from] ) if( from < to ) { start1[from,to] <- x start2[from,to] <- y } else if( from > to ) { end1[to,from] <- x end2[to,from] <- y } else { # no loops allowed } x <- y } } par(mar=c(1,1,2,1)) plot( 0,0, xlim=c(-1,1),ylim=c(-1,1), type="n", axes=FALSE, main="Two qualitative variables in polar coordinates", xlab="", ylab="") for(from in 1:n) { for(to in 1:n) { if(from<to) { u <- start1[from,to] v <- start2[from,to] x <- end1 [from,to] y <- end2 [from,to] if(!is.na(u*v*x*y)) { r1 <- poincare_segment( cos(2*pi*v), sin(2*pi*v), cos(2*pi*x), sin(2*pi*x) ) r2 <- poincare_segment( cos(2*pi*y), sin(2*pi*y), cos(2*pi*u), sin(2*pi*u) ) th1 <- 2*pi*seq(u,v,length=20) th2 <- 2*pi*seq(x,y,length=20) polygon( c( cos(th1), r1$x, rev(cos(th2)), r2$x ), c( sin(th1), r1$y, rev(sin(th2)), r2$y ), col=transparent_segment_colour[from], border=NA ) } } } } for(i in 1:n) { theta <- 2*pi*seq(segment_start[i], segment_end[i], length=100) r1 <- 1 r2 <- 1.05 polygon( c( r1*cos(theta), rev(r2*cos(theta)) ), c( r1*sin(theta), rev(r2*sin(theta)) ), col=segment_colour[i], border="black" ) }