正则表达式：查找不以特定前缀开头的字符串[重复](regex: find strings that do not begin with a certain prefix [duplicate])

正则表达式：查找不以特定前缀开头的字符串[重复](regex: find strings that do not begin with a certain prefix [duplicate])

这个问题在这里已有答案：

不以序列 1答案 开头的字符串的正则表达式

我想在字符串中找到一个单词，但前提是它不以前缀开头 。

例如。

我想找到APP_PERFORM_TASK的所有外观，但前提是它们没有以CMD_DO的前缀开头（“

所以，

CMD_DO("APP_PERFORM_TASK") <- OK (i don't need to know about this) BLAH("APP_PERFORM_TASK") <-- NOT OK, this should match my search.

我试过了：

(?!CMD_DO\(")APP_PERFORM_TASK

但这并不能产生我需要的结果。 我做错了什么？

This question already has an answer here:

Regular expression for a string that does not start with a sequence 1 answer

I want to find a word in strings, but only if it doesn't begin with a prefix.

for example.

I'd like to find all the appearances of APP_PERFORM_TASK, but only if they are not starting with a prefix of CMD_DO("

so,

CMD_DO("APP_PERFORM_TASK") <- OK (i don't need to know about this) BLAH("APP_PERFORM_TASK") <-- NOT OK, this should match my search.

I tried:

(?!CMD_DO\(")APP_PERFORM_TASK

But that doesn't produce the results I need. What I doing wrong?

最满意答案

这是一个快速的方法：

使用--invert-match（也称为-v）标志来忽略CMD_DO并将结果传递给仅与BLAH匹配的第二个grep：

grep -v CMD_DO dummy | grep BLAH

Here's a quick way:

Use the --invert-match (also known as -v) flag to ignore CMD_DO and pipe the results to a second grep that only matches BLAH:

grep -v CMD_DO dummy | grep BLAH