如何在Python的集合中执行most

如何在Python的集合中执行most_common时忽略大小写。计数器？(How to ignore case while doing most_common in Python's collections.Counter?)

我正在尝试使用collections模块中的most_common迭代中元素的出现次数。

>>> names = ['Ash', 'ash', 'Aish', 'aish', 'Juicy', 'juicy'] >>> Counter(names).most_common(3) [('Juicy', 1), ('juicy', 1), ('ash', 1)]

但我的期望是，

[('juicy', 2), ('ash', 2), ('aish', 2)]

是否存在“pythonic”方式/技巧来合并'ignore-case'功能，以便我们可以获得所需的输出。

I'm trying to count the number of occurrences of an element in an iterable using most_common in the collections module.

>>> names = ['Ash', 'ash', 'Aish', 'aish', 'Juicy', 'juicy'] >>> Counter(names).most_common(3) [('Juicy', 1), ('juicy', 1), ('ash', 1)]

But what I expect is,

[('juicy', 2), ('ash', 2), ('aish', 2)]

Is there a "pythonic" way/trick to incorporate the 'ignore-case' functionality , so that we can get the desired output.

最满意答案

把它映射到str.lower怎么str.lower ？

>>> Counter(map(str.lower, names)).most_common(3) [('juicy', 2), ('aish', 2), ('ash', 2)]

How about mapping it to str.lower?

>>> Counter(map(str.lower, names)).most_common(3) [('juicy', 2), ('aish', 2), ('ash', 2)]