问题描述
限时送ChatGPT账号..所以我用 C 编码,我需要想出一些代码,从用户那里获取 n 个数字,并找到它们的最小值、最大值、平均值和平方和的值.到目前为止,我有平方和的平均值和总和部分,但最小值和最大值正在咬我.
So I'm coding in C, and I need to come up with code that will take n numbers from the user, and find their minimum, maximum, average, and sum of squares for for their values. So far I have the average and sum of squares portion, but the minimum and maximum is biting me.
请记住,我处于非常初级的水平,还没有达到数组.我只知道逻辑运算符、函数、循环以及 stdlib.h、math.h 和 stdio.h 库的使用.
Keep in mind I'm at a very rudimentary level, and I have not reached arrays yet. All I know are logical operators, functions, loops, and the use of the stdlib.h, math.h, and stdio.h libraries.
这是我目前所拥有的.当我在编译期间尝试放置 float 和 double 时,平均函数给我带来了很多问题,因此将其乘以 1.0 修复了该问题.我拥有一切,只有最低限度和最高限度.我一直把最后一个条目作为我的最大值,0 代表我的最小值.
This is what I have so far. The average function gave me a lot of problems when I tried to put float and double during compiling, so multiply it by a 1.0 fixed that. I have everything, just the minimum and maximum. I keep getting the last entry as my maximum, and a 0 for my minimum.
#include<stdio.h>
int main()
{
float average;
int i, n, count=0, sum=0, squaresum=0, num, min, max;
printf("Please enter the number of numbers you wish to evaluate\n");
scanf_s("%d",&n);
printf("Please enter %d numbers\n",n);
while(count<n)
{
min=0;
max=0;
if(num>max)
max=num;
if(num<min)
min=num;
scanf_s("%d",&num);
sum = sum+num;
squaresum = squaresum + (num*num);
count++;
}
average = 1.0*sum/n;
printf("Your average is %.2f\n",average);
printf("The sum of your squares is %d\n",squaresum);
printf("Your maximum number is %d\n",max);
printf("Your minimum number is %d\n",min);
return(0);
}
推荐答案
你的算法不太对.下面是正确的实现:
Your algorithm is not quite right. Below is the correct implementation:
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
int main(void)
{
float average;
int n, num, count = 0, sum = 0, squaresum = 0;
int min = INT_MAX, max = INT_MIN;
bool gotAnswer = false;
/* Don't Let User Enter Wrong Input */
while(!gotAnswer)
{
printf("Please enter the number of numbers you wish to evaluate: ");
if(scanf_s("%d", &n) != 1)
{
/* User Entered Wrong Input; Clean Up stdin Stream*/
while(getchar() != '\n')
{
continue;
}
}
else
{
/* User Input Was Good */
gotAnswer = true;
}
}
/* Clear stdin Stream Just In Case */
while(getchar() != '\n')
continue;
while(count < n)
{
/* Don't Let User Enter Wrong Input */
gotAnswer = false;
printf("Enter number %d: ", count + 1);
if(scanf_s("%d", &num) != 1)
{
/* User Entered Wrong Input; Clean Up stdin Stream */
while(getchar() != '\n')
continue;
/* Let User Try Again */
continue;
}
else
{
/* User Input Was Correct */
gotAnswer = true;
/* Clear stdin Stream Just In Case */
while(getchar() != '\n')
continue;
}
if(num > max)
max = num;
if(num < min)
min = num;
sum += num;
squaresum += num * num;
count++;
}
average = 1.0 * sum / n;
printf("Your average is %.2f\n", average);
printf("The sum of your squares is %d\n", squaresum);
printf("Your maximum number is %d\n", max);
printf("Your minimum number is %d\n", min);
system("pause");
return 0;
}
我添加了错误检查和恢复.如果您对逻辑有任何疑问,请提问.
I've added error checking and recovery. Please ask if you have any questions about the logic.
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