scanf 签入 while 循环以限制整数输入

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问题描述

限时送ChatGPT账号..

我正在编写一个代码，要求用户输入 10 个整数，然后将这些整数向后反馈给他.我想创建一个scanf 检查"来限制字符输入.while 循环的工作原理是它不接受字符，但会跳过整数输入.

I am writing a code asking the user to input 10 integers, which are then fed to him backwards. I would like to create a "scanf check" to restrict character input. The while loop works insofar that it doesn't accept char, but it skips a integer input.

int main()
{

    int i = 0, number[10] = {0};
    char buf[128] = {0};

    for (i = 0; i < 10; i++)
    {
      printf("Please input number %d : ", i+1);

         while(scanf("%d", &number[i]) != 1)
      {
         scanf("%s", &buf);
         printf("Sorry, [%s] is not a number. Please input number %d : ", &buf, i);
      }
    }

    for (i = 0; i < 10; i++)
    {
    printf("\n Number %d is %d", (10-i), number[9-i]);
    }

    return EXIT_SUCCESS;
}

推荐答案

正如 H2CO3 所指出的，不要使用 scanf，替代方案是 fgets 和 strtol:

As pointed out by H2CO3, don't use scanf, an alternative is fgets and strtol:

int i, number[10] = {0};
char buf[128], *p;

for (i = 0; i < 10; i++) {
    printf("Please input number %d : ", i+1);
    while (1) {
        fgets(buf, sizeof(buf), stdin);
        if ((p = strchr(buf, '\n')) != NULL) {
            *p = '\0';
        }
        number[i] = (int)strtol(buf, &p, 10);
        if (p == buf || *p != '\0')  {
            printf("Sorry, [%s] is not a number. Please input number %d : ", buf, i + 1);
        } else {
            break;
        }  
    }
}
for (i = 0; i < 10; i++) {
    printf("\n Number %d is %d", (10-i), number[9-i]);
}
return EXIT_SUCCESS;

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