如何使用Python只显示带元音的单词中的字母(How to use Python to show only the letters from words with vowels)

如何使用Python只显示带元音的单词中的字母(How to use Python to show only the letters from words with vowels) VOWELS = "aeiou" word = "matt" word = "james is funny" cnt = 0 for v1 in VOWELS: print ("vowel", cnt) print("letter:", v1) cnt = cnt + 1 for v1 in word: print ("location in string", cnt) print("letter:", v1) cnt = cnt + 1

我一直试图弄清楚这几个小时，这让我发疯。 我只需要python来打印单词中的元音字母。

VOWELS = "aeiou" word = "matt" word = "james is funny" cnt = 0 for v1 in VOWELS: print ("vowel", cnt) print("letter:", v1) cnt = cnt + 1 for v1 in word: print ("location in string", cnt) print("letter:", v1) cnt = cnt + 1

I've been trying to figure this out for hours and it's driving me crazy. I just need python to print only the vowel letters in the words.

最满意答案

直截了当的方式：

对于文本中的每个字母 如果它是一个元音，打印它 否则打印一个空格

直接转换为Python（以及在打印时将所有内容保持在同一行上的调整）：

VOWELS = "aeiou" word = "james is funny" for letter in word: if letter in VOWELS: print(letter, end='') else: print(' ', end='')

或者稍微更花哨的方式：

用空格替换所有非元音。 打印结果

使用正则表达式模式语言：

import re word = "james is funny" new_word = re.sub('[^aeiou]', ' ', 'james is funny') print new_word

The straightforward way:

for each letter in the text if it is a vowel, print it otherwise print a space

Translates directly into Python (along with a tweak to keep everything on the same line when printing):

VOWELS = "aeiou" word = "james is funny" for letter in word: if letter in VOWELS: print(letter, end='') else: print(' ', end='')

Or the slightly more fancy way:

Replace all non-vowels with spaces. Print the result

Using the regular expression pattern language:

import re word = "james is funny" new_word = re.sub('[^aeiou]', ' ', 'james is funny') print new_word