Opengl让“AI”桨上下移动(Opengl make “AI” paddle move up and down)

Opengl让“AI”桨上下移动(Opengl make “AI” paddle move up and down)

我有点像一个openGL /编程noobie所以我试图为正确的桨做一个“AI”。 我知道这不是正确的做法，我应该做的是让它跟随球。 但是现在我只是想让它不断上下移动。 我无法弄清楚如何做到这一点，尝试使用If循环之类的

if（paddle.pos [1]> 1）{paddle.pos [1] = paddle.pos [1] - delta}

我将delta设置为0.01之类，1是屏幕的顶部。 显然这不对，因为一旦它低于1它再次上升，但我正在尝试做类似的事情。

第二个问题 - 当球开始时你如何将球从0,0移开？ 有点同样的问题，我使用带有x值的if语句，但这绝对不对。

这顺便使用C.

I'm a bit of an openGL/programming noobie so I'm trying to make an "AI" for the right paddle. I know this isnt the proper way of doing it, what I SHOULD be doing is making it follow the ball. But right now I'm just trying to make it perpetually move up and down. I can't figure out how to do it, trying to use If loops like

if (paddle.pos[1] > 1){ paddle.pos[1] = paddle.pos[1] - delta}

I set delta to something like 0.01, 1 is the top of the screen. Obviously this isnt right because as soon as it goes down below 1 it goes up again, but I'm trying to do something like it.

2nd question - How do you move the ball from 0,0 when it starts? Kind of the same problem, am using if statements with the x values but thats definitely not right.

This is using C by the way.

最满意答案

尝试这样的方法使pos重复从0到1再回到0：

// Initialize. float pos = 0.0f; float delta = 0.01f; // On every update. pos += delta; if (pos > 1.0f) { pos = 1.0f; delta = -delta; } else if (pos < 0.0f) { pos = 0.0f; delta = -delta; }

这里的关键是每次到达其中一个结束位置时都会反转增量的符号。

Try something like this to make pos repeatedly go from 0 to 1 and back to 0:

// Initialize. float pos = 0.0f; float delta = 0.01f; // On every update. pos += delta; if (pos > 1.0f) { pos = 1.0f; delta = -delta; } else if (pos < 0.0f) { pos = 0.0f; delta = -delta; }

The key here is that you invert the sign of your increment each time you reach one of the end positions.