jQuery：获取最后一行列选择器(jQuery: Get last row column selector)

jQuery：获取最后一行列选择器(jQuery: Get last row column selector)

我在表中有以下行：

<tr><td>Adric cut-out</td><td><span class="quantity">0</span></td><td>worthless</td></tr>

我已经选择了“数量”类的跨度，但我没有运气获得所选行中的最后一个TD元素。 我可以通过获取它的父级，然后是它的父级，然后是最后一个TD子元素来实现它，但是有更高效的东西吗？

以此为开头，我如何选择包含价格的TD元素？ 请注意，它始终是该行的最后一项。

I have the following row in a table:

<tr><td>Adric cut-out</td><td><span class="quantity">0</span></td><td>worthless</td></tr>

I've already got the span with the class 'quantity' selected, but I'm having no luck getting the last TD element in the row selected. I can do it by getting its parent, then its parent, then the last TD child element but is there something a little more efficient?

Using this as a start, how would I select the TD element containing the price? Note, it will always be the last item on the row.

最满意答案

如果格式一致，那么升级到下一列应该相当有效：

var price = $('.quantity').closest('td').next().html();

简单地将一个类（ price ？）分配给最后一个td并收集它可能会更快。

If the format is consistent, stepping up and over to the next column should be fairly efficient:

var price = $('.quantity').closest('td').next().html();

It might be faster to simply assign a class (price?) to the last td and collect that, though.