如何有条件地读取所有属性?

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我想使用where子句读取所有可枚举的属性.

I want to read all attributes as I Enumerable using where clause.

所以我想要的是将Employee返回为List，其中List = PayList

So what I want is return Employee as List where List = PayList

下面是我的XML.

<Employees Table="ListColumns" StartAt="1" Output="Return"> <Lists List="PayList"> <Employee Start="51" Length="11" Name="Amount"/> <Employee Start="62" Length="6" Name="Name"/> <Employee Start="68" Length="50" Name="Reason"/> <Employee Start="118" Length="7" Name="Action"/> <Employee Start="125" Length="6" Name="First"/> <Employee Start="131" Length="6" Name="Last"/> <Employee Start="137" Length="40" Name="Payee"/> <Employee Start="177" Length="6" Name="Banker"/> <Employee Start="183" Length="19" Name="DateIssued"/> <Employee Start="202" Length="19" Name="DateStopped"/> </Lists> <Lists List="ResponseList"> <Employee Start="51" Length="11" Name="Amount"/> <Employee Start="62" Length="6" Name="Name"/> <Employee Start="68" Length="50" Name="Reason"/> <Employee Start="118" Length="7" Name="Action"/> <Employee Start="125" Length="6" Name="First"/> <Employee Start="131" Length="6" Name="Last"/> <Employee Start="137" Length="40" Name="Payee"/> <Employee Start="177" Length="6" Name="Banker"/> <Employee Start="183" Length="19" Name="DateIssued"/> <Employee Start="202" Length="19" Name="DateStopped"/> </Lists> </Employees>

Ashwani Vashishtha

Ashwani Vashishtha

推荐答案

var lists = from ls in XDocument.Load(@"C:\TEMP\Employee.xml").Descendants("Lists") where ls.Attribute("List").Value == "PayList" select ls; var employees = from emp in lists.Descendants("Employee") select new Employee { Start = emp.Attribute("Start").Value, Length = emp.Attribute("Length").Value, Name = emp.Attribute("Name").Value };