Laravel可选路线参数

本文介绍了Laravel可选路线参数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 Route::get('dashboard/{path?}', function($path= null) { return $path; });

是的，是的

如果网址是

仪表板/电影/搞笑/../..

获取 NotFoundHttpException

推荐答案

默认情况下为路由参数不能包含任何斜杠，因为多个路由参数或线段之​​间用斜杠分隔。

Per default a route parameter cannot contain any slashes, because multiple route parameters or segments are separated by slashes.

如果路径级别有限，则可以执行以下操作：

If you have a finite number of path levels you could do this:

Route::get('dashboard/{path1?}/{path2?}/{path3?}', function($path1 = null, $path2 = null, $path3 = null)

但是，这不是很优雅，也不动态，您的示例表明可能存在很多路径级别。您可以使用where约束在route参数中使用斜线，因此该路由基本上可以捕获以 dashboard 开头的所有内容p>

However this isn't very elegant nor dynamic and your example suggests there can be many path levels. You can use a where constraint to allow slashes in the route parameter. So this route will basically catch everything that starts with dashboard

Route::get('dashboard/{path?}', function($path= null){ return $path; })->where('path', '(.*)');