跳过范围内的角色(Skip a character in range)

跳过范围内的角色(Skip a character in range)

我有一个正则表达式： /["-,]/它匹配范围内的字符: to ,我想跳过' （撇号）的匹配。任何帮助!!

regex.test(strInput);

对于带有撇号的字符串，它返回true。 我需要否定那个有撇号的字符串

I have a regular expression : /["-,]/ Which matches a character in range of : to , I want to skip the match for '(apostrophe). Any help !!

regex.test(strInput);

is returning true for a string with an apostrophe. I need to negate that string which has an apostrophe

最满意答案

您可以使用否定前瞻：

/(?!')["-,]/

这里(?!')是负向前瞻 ，这意味着下一个字符不能是单引号。

You can use negative lookahead:

/(?!')["-,]/

Here (?!') is negative lookahead which means next character must not be single quote.