我想要做的就是一些数据从一个的的HttpURLConnection 而不是使用 JsonObjectRequest()从凌空库。
What I'm trying to do is get some data from a HttpURLConnection instead of using JsonObjectRequest() from the Volley library.
下面是我用它来从我的服务器抓取一个JSON对象的code。
Below is the code that I use to grab a JSON object from my server.
JsonObjectRequest jsonReq = new JsonObjectRequest(Method.GET,"myURL", null, new Response.Listener<JSONObject>();
我试图改变空到的JSONObject 在 myURL 改为空。但是,这并没有工作了。
I tried changing the null to a JSONObject after myURL was changed to null. But that did not work out.
推荐答案在 JsonObjectRequest网址()不可选的,JSONObject的参数是用来发布的参数与请求的URL。
The url in JsonObjectRequest() is not optional, and the JSONObject parameter is used to post parameters with the request to the url.
从文档: afzaln/volley/com/android/volley/toolbox/JsonObjectRequest.html
developer.android/training/volley/index.html
JsonObjectRequest
JsonObjectRequest
公共JsonObjectRequest(INT方法, 字符串URL, 的JSONObject jsonRequest, Response.Listener监听器, Response.ErrorListener errorListener)创建一个新的请求。
public JsonObjectRequest(int method, String url, JSONObject jsonRequest, Response.Listener listener, Response.ErrorListener errorListener) Creates a new request.
参数:
方法 - HTTP方法使用
method - the HTTP method to use
URL - URL从
url - URL to fetch the JSON from
jsonRequest - 一个JSONObject的发布与请求。空是允许的 并表示没有参数,将张贴与要求。
jsonRequest - A JSONObject to post with the request. Null is allowed and indicates no parameters will be posted along with request.
监听器 - 监听器接收JSON响应
listener - Listener to receive the JSON response
errorListener - 错误监听,或者为null,忽略错误
errorListener - Error listener, or null to ignore errors.
使用的HttpURLConnection :
developer.android/reference/java/net/HttpURLConnection.html
在code将是这样的:
The code would be something like this:
public class getData extends AsyncTask<String, String, String> { HttpURLConnection urlConnection; @Override protected String doInBackground(String... args) { StringBuilder result = new StringBuilder(); try { URL url = new URL("api.github/users/dmnugent80/repos"); urlConnection = (HttpURLConnection) url.openConnection(); InputStream in = new BufferedInputStream(urlConnection.getInputStream()); BufferedReader reader = new BufferedReader(new InputStreamReader(in)); String line; while ((line = reader.readLine()) != null) { result.append(line); } }catch( Exception e) { e.printStackTrace(); } finally { urlConnection.disconnect(); } return result.toString(); } @Override protected void onPostExecute(String result) { //Do something with the JSON string } }更多推荐
如何使用HttpURLConnection的,而不是凌空获得JSON对象?
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