我正在使用Scalatra,后者又使用Json4S生成Json字符串.我收到
I am using Scalatra, which in turn uses Json4S to generate Json string. I receive
["A","B"]
["A","B"]
对于
List(Some("A"),None,Some("B"))
List(Some("A"),None,Some("B"))
我想收到
["A",未定义,"B"]
["A",undefined,"B"]
如何解决?
推荐答案undefined即使在javascript中有效,也不是有效的json值. 来自 rfc4627 (应用程序/json):
undefined is not a valid json value, even though it is valid in javascript. From rfc4627 (application/json):
JSON值必须是对象,数组,数字或字符串,或者是以下之一 以下三个文字名称:
A JSON value MUST be an object, array, number, or string, or one of the following three literal names:
false null真
false null true
(未提及未定义)
但是,与null而不是undefined相比,这很简单.在scala控制台中,首先导入几个:
However this is fairly straight-forward to do with null instead of undefined. In the scala console, first a couple imports:
scala> import org.json4s._ scala> import org.json4s.native.Serialization.write客户序列化程序:
scala> class NoneJNullSerializer extends CustomSerializer[Option[_]](format => ({ case JNull => None }, { case None => JNull }))瞧,
scala> implicit val formats = DefaultFormats + new NoneJNullSerializer() scala> val ser = write(List(Some("A"), None, Some("B"))) ser: String = ["A",null,"B"]更多推荐
从包含Some和None值的列表中使用Json4S生成Json字符串
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