如何在Scala中使用Json4s序列化密封的抽象类?
How do i serialize a sealed abstract class with Json4s in Scala?
定义了以下类:
sealed abstract class Person extends Product with Serializable case class Spouse(name: String, age: Int) extends Person case class Customer(name: String, age: Int, spouse: Spouse) extends Person我创建了一个Customer类型的对象:
I create an object of type Customer:
val customer: Customer = Customer("Joe", 35, Spouse("Marilyn", 33))然后我序列化为JSON:
Then I serialize to JSON:
implicit val formats = DefaultFormats val serialized = write(customer)那很好.但随后我尝试反序列化:
That works fine. But then I try to deserialize:
val parsedObj = Serialization.read[Person](serialized)在这里我总是收到错误消息:
Here I keep getting error:
org.json4s.package $ MappingException:解析的JSON值与类构造函数不匹配
org.json4s.package$MappingException: Parsed JSON values do not match with class constructor
我花了很多时间试图使这项工作...
I spent a lot of time trying to make this work...
推荐答案经过大量的搜索并仔细阅读了Json4s文档后,我发现我需要一个自定义的Serializer才能使其正常工作.
After a lot of googling around and a close read of the Json4s documentation i found out that I need a custom Serializer to make it work.
但是,我花了一段时间才弄清楚我需要设置格式实际使用自定义序列化器.
However, it took me a while to figure out that I need to set the formats to actually use the custom Serializer.
这是对我有用的代码.
简单示例:
import org.json4s._ import org.json4s.native.JsonMethods._ import org.json4s.native.Serialization.{read, write} import org.json4s.native.Serialization sealed abstract class Person extends Product with Serializable case class Spouse(name: String, age: Int) extends Person case class Customer(name: String, age: Int, spouse: Spouse) extends Person val customer: Customer = Customer("Joe", 35, Spouse("Marilyn", 33)) implicit val formats = Serialization.formats(NoTypeHints) + PersonSerializer val serialized = write(customer) val parsedObj = Serialization.read[Person](serialized)自定义序列化器:
object PersonSerializer extends Serializer[Person] { private val PersonClass = classOf[Person] def deserialize(implicit format: Formats) : PartialFunction[(TypeInfo, JValue), Person] = { case (TypeInfo(PersonClass, _), json) => json match { case JObject(List( JField("name", JString(d)), JField("age", JInt(f)), ("spouse", JObject(List(JField("name", JString(g)), JField("age", JInt(h))))) )) => Customer(d, f.toInt, Spouse(g, h.toInt)) case JObject(List( JField("name", JString(d)), JField("age", JInt(f)) )) => Spouse(d, f.toInt) } } def serialize(implicit format: Formats): PartialFunction[Any, JValue] = { case x: Customer => JObject(List( JField("name", JString(x.name)), JField("age", JInt(x.age)), ("spouse", JObject(List(JField("name", JString(x.spouse.name)), JField("age", JInt(x.spouse.age))))) )) case x: Spouse => JObject(List( JField("name", JString(x.name)), JField("age", JInt(x.age)) )) } }输出
scala> val serialized = write(customer)
scala> val serialized = write(customer)
序列化:字符串= {名称":"Joe",年龄":35,配偶":{名称":"Marilyn",年龄":33}}
serialized: String = {"name":"Joe","age":35,"spouse":{"name":"Marilyn","age":33}}
scala> val parsedObj = Serialization.readPerson
scala> val parsedObj = Serialization.readPerson
parsedObj:人员=客户(Joe,35,Spouse(Marilyn,33))
parsedObj: Person = Customer(Joe,35,Spouse(Marilyn,33))
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如何在Scala中使用Json4s序列化密封的抽象类?
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