@JsonIgnore使用Jackon和Json4s序列化Scala案例类属性

本文介绍了@JsonIgnore使用Jackon和Json4s序列化Scala案例类属性的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在尝试阻止Scala 案例类的某个属性被序列化。我尝试使用通常的 @JsonIgnore 注释相关属性，我也尝试附加 @JsonIgnoreProperties（Array（property_name）） ）到案例类。这两者似乎都达不到我想要的。

I'm trying to prevent one of the properties of a Scala case class being serialised. I've tried annotating the property in question with the usual @JsonIgnore and I've also tried attaching the @JsonIgnoreProperties(Array("property_name")) to the case class. Neither of which seem to achieve what I want.

以下是一个小例子：

import org.json4s._ import org.json4s.jackson._ import org.json4s.jackson.Serialization import org.json4s.jackson.Serialization.{read, write} import com.fasterxml.jackson.annotation._ object Example extends App { @JsonIgnoreProperties(Array("b")) case class Message(a: String, @JsonIgnore b: String) implicit val formats = Serialization.formats(NoTypeHints) val jsonInput = """{ "a": "Hello", "b":"World!" }""" val message = read[Message](jsonInput) println("Read " + message) // "Read Message(Hello,World!) val output = write(message) println("Wrote " + output) // "Wrote {"a":"Hello","b":"World!"}" }

推荐答案

将@JsonIgnore更改为@JsonProperty（b）。你有正确地声明忽略财产'b但是'b还没有安作为一个属性。

Change your @JsonIgnore to @JsonProperty("b"). You have correctly stated to Ignore the property 'b but 'b has not yet been annotated as a property.

@JsonIgnoreProperties(Array("b")) case class Message(a: String, @JsonProperty("b") b: String)