从Java API我得到
from Java API I get
java.util.LinkedHashMap[String,java.util.ArrayList[String]]然后我需要将其作为参数传递给 Scala 程序
which I then need to pass as a parameter to a scala program
val rmap = Foo.baz(parameter)这个参数是scala类型的:
This parameter is of scala type:
Map[String,List[String]]那么我怎样才能轻松转换
So how can I easily convert
java.util.LinkedHashMap[String,java.util.ArrayList[String]]到
Map[String,List[String]]我尝试使用 import scala.collection.JavaConversions._ 但在我的情况下这不起作用(或者至少我猜是这样)因为 scala 代码在模板函数中,我只能放置 import scala.collection.JavaConversions._ 函数内部.模板函数是这样的:
I tried using import scala.collection.JavaConversions._ but in my case this does not work (or at least thats what I guess) because the scala code is in template function and I can only place import scala.collection.JavaConversions._ inside the function. the template function is like:
def someFunc(param: java.util.LinkedHashMap[String,java.util.ArrayList[String]]) = { import scala.collection.JavaConversions._ val rmap = Foo.baz(param) // param is of scala type Map[String,List[String]] .......现在scala不会自动将java类型转换为scala类型.
Now scala is not auto converting java type to scala type.
这是我得到的编译器错误:引发的错误是:类型不匹配;发现:java.util.LinkedHashMap[String,java.util.ArrayList[String]] 需要:Map[String,List[String]]
This is the compiler error I get: Error raised is : type mismatch; found : java.util.LinkedHashMap[String,java.util.ArrayList[String]] required: Map[String,List[String]]
推荐答案你有两个问题:scala 中的 Map 和 List 与 java 版本不同.
You've got two problems: Map and List in scala are different from the java versions.
scala.collection.JavaConversions.mapAsScalaMap 创建一个可变映射,因此使用可变映射,以下工作:
scala.collection.JavaConversions.mapAsScalaMap creates a mutable map, so using the mutable map, the following works:
import scala.collection.JavaConversions._ import scala.collection.mutable.Map val f = new java.util.LinkedHashMap[String, java.util.ArrayList[String]] var g: Map[String, java.util.ArrayList[String]] = fArrayList 有点难.以下工作:
The ArrayList is a bit harder. The following works:
import scala.collection.JavaConversions._ import scala.collection.mutable.Buffer val a = new java.util.ArrayList[String] var b: Buffer[String] = a但是如果我们尝试
import scala.collection.JavaConversions._ import scala.collection.mutable.Map import scala.collection.mutable.Buffer val f = new java.util.LinkedHashMap[String, java.util.ArrayList[String]] var g: Map[String, Buffer[String]] = f这不起作用.您最好的选择是为此自己定义显式隐式转换.
this doesn't work. Your best option is to define an explicit implicit conversion yourself for this.
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