以格式yyyymmddHHMM创建日期序列，在bash中增加12小时(Create sequence of dates in format yyyymmddHHMM with 12 hour incr

以格式yyyymmddHHMM创建日期序列，在bash中增加12小时(Create sequence of dates in format yyyymmddHHMM with 12 hour increment in bash)

Tl; dr ：在bash中以yyyymmddHHMM格式创建一个12小时递增的日期序列是否有很好的方法？

考虑我有一个python脚本，它接受一定的时间（yyyymmddHHMM）作为输入-t，我可以这样运行它，例如

python myscript.py -t 201411140000

然后开始myscript.py为2014-11-14 00:00。 现在我想运行许多日期的脚本，从2014-01-01 00:00到2014-11-14 00:00开始，增量为12小时，即我想生成以下所有行：

python myscript.py -t 201401010000 python myscript.py -t 201401011200 python myscript.py -t 201401020000 . . . python myscript.py -t 201411131200 python myscript.py -t 201411140000

最接近我的是（回声以验证结果而不运行它们）：

for mm in {01..10}; do for dd in {01..31}; do for HH in 00 12; do echo python myscript.py -t 2014$mm$dd$HH\00; done; done; done

它产生从1月到10月的所有必需日期，但也有一些荒谬的日期 ，例如201402310000 ，程序然后必须处理（即抛出/记录错误）。 这不是一个大问题，但感觉很脏。 最后，需要另一个循环来处理11月1日至11月14日的缺失日期，这对我来说再次变得肮脏。

我怎样才能更好地创建这些日期 - 或者是否超出了适当的方式？

Tl;dr: Is there a nice way of creating a sequence of dates with 12 hour increment in the format yyyymmddHHMM in the bash?

Consider I have a python-script which accepts a certain time (yyyymmddHHMM) as input -t, i could run it like this for instance

python myscript.py -t 201411140000

which the then starts myscript.pyfor the date 2014-11-14 00:00. Now I want to run the script for many dates, beginning from 2014-01-01 00:00 to 2014-11-14 00:00 with an increment of 12 hours, i.e. i want to produce all the following lines:

python myscript.py -t 201401010000 python myscript.py -t 201401011200 python myscript.py -t 201401020000 . . . python myscript.py -t 201411131200 python myscript.py -t 201411140000

The closest to what I came is (echo to verify results without running them):

for mm in {01..10}; do for dd in {01..31}; do for HH in 00 12; do echo python myscript.py -t 2014$mm$dd$HH\00; done; done; done

It produces all required dates from Jan to Oct, but also some absurd dates, such as 201402310000, which the program then has to handle (i.e. throw/log errors). That is not a huge issue, but it feels dirty. In the end, another loop is required to handle the missing dates Nov-01 to Nov-14, which, again, seems dirty to me.

How can I create those dates more nicely - or is the way above the appropriate way of doing so?

最满意答案

您可以将开始日期转换为UNIX时间戳，并以43200秒（12小时）为增量迭代该范围。

for ((ts=$(date +%s --date "2014-11-01 0000"); ts <= $(date +%s --date "2014-11-14 0000"); ts+=12*3600)); do python myscript.py -t $(date +%Y%m%d%H%M --date @$ts) done

You can convert the start date to a UNIX timestamp, and iterate over the range in 43200-second (12-hour) increments.

for ((ts=$(date +%s --date "2014-11-01 0000"); ts <= $(date +%s --date "2014-11-14 0000"); ts+=12*3600)); do python myscript.py -t $(date +%Y%m%d%H%M --date @$ts) done