如何在redshift中查找数据库，架构，表的大小

本文介绍了如何在redshift中查找数据库，架构，表的大小的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

团队

我的redshift版本是:

my redshift version is:

PostgreSQL 8.0.2 on i686-pc-linux-gnu, compiled by GCC gcc (GCC) 3.4.2 20041017 (Red Hat 3.4.2-6.fc3), Redshift 1.0.735

如何找出数据库大小，表空间，架构大小&桌子大小?

how to find out database size, tablespace, schema size & table size ?

但以下版本在redshift中不起作用(对于以上版本)

but below are not working in redshift ( for above version )

SELECT pg_database_size('db_name'); SELECT pg_size_pretty( pg_relation_size('table_name') );

是否有其他方法可以找到类似oracle(从DBA_SEGMENTS)

Is there any alternate to find out like oracle ( from DBA_SEGMENTS )

对于tble的大小，我有以下查询，但不确定MBYTES的确切功能.对于第三行，MBYTES =372.这意味着372 MB?

for tble size, i have below query, but not sure about exact menaing of MBYTES. FOR 3rd row, MBYTES = 372. it means 372 MB ?

select trim(pgdb.datname) as Database, trim(pgn.nspname) as Schema, trim(a.name) as Table, b.mbytes, a.rows from ( select db_id, id, name, sum(rows) as rows from stv_tbl_perm a group by db_id, id, name ) as a join pg_class as pgc on pgc.oid = a.id join pg_namespace as pgn on pgn.oid = pgc.relnamespace join pg_database as pgdb on pgdb.oid = a.db_id join (select tbl, count(*) as mbytes from stv_blocklist group by tbl) b on a.id=b.tbl order by a.db_id, a.name; database | schema | table | mbytes | rows ---------------+--------------+------------------+--------+---------- postgres | public | company | 8 | 1 postgres | public | table_data1_1 | 7 | 1 postgres | proj_schema1 | table_data1 | 372 | 33867540 postgres | public | table_data1_2 | 40 | 2000001 (4 rows)

推荐答案

以上答案并不总是为使用的表空间提供正确答案. AWS支持已将此查询使用:

The above answers don't always give correct answers for table space used. AWS support have given this query to use:

SELECT TRIM(pgdb.datname) AS Database, TRIM(a.name) AS Table, ((b.mbytes/part.total::decimal)*100)::decimal(5,2) AS pct_of_total, b.mbytes, b.unsorted_mbytes FROM stv_tbl_perm a JOIN pg_database AS pgdb ON pgdb.oid = a.db_id JOIN ( SELECT tbl, SUM( DECODE(unsorted, 1, 1, 0)) AS unsorted_mbytes, COUNT(*) AS mbytes FROM stv_blocklist GROUP BY tbl ) AS b ON a.id = b.tbl JOIN ( SELECT SUM(capacity) AS total FROM stv_partitions WHERE part_begin = 0 ) AS part ON 1 = 1 WHERE a.slice = 0 ORDER BY 4 desc, db_id, name;