使用awk获取数组中参数的值(Use awk to get value of the parameter in the array)

使用awk获取数组中参数的值(Use awk to get value of the parameter in the array)

journalctl -b向我展示了这样的日志：

something something somethng aaa: 0x00000111 bbb: 0x00000222 ccc: 0x00000333 ddd: 0x00000444 something something somethng

如何获得参数'ccc'的值？

例如：

journalctl -b | awk '/ccc:/{print $1}'

显示第一个字，但我需要在'ccc'之后得到第一个字：

0x00000333

journalctl -b showed me log like this:

something something somethng aaa: 0x00000111 bbb: 0x00000222 ccc: 0x00000333 ddd: 0x00000444 something something somethng

How to get value of parameter 'ccc'?

For example:

journalctl -b | awk '/ccc:/{print $1}'

showed first word, but I need to get first word after 'ccc':

0x00000333

最满意答案

使用sed ：

$ echo "aaa: 0x00000111 bbb: 0x00000222 ccc: 0x00000333 ddd: 0x00000444"|sed 's/.*ccc: \([^ ]*\).*/\1/g' 0x00000333

如果你真的想使用awk ：

$ echo "aaa: 0x00000111 bbb: 0x00000222 ccc: 0x00000333 ddd: 0x00000444"|awk '/ccc:/{s=$0; gsub(".*ccc: ", "", s); gsub(" .*$", "", s); print s}' 0x00000333

Using sed:

$ echo "aaa: 0x00000111 bbb: 0x00000222 ccc: 0x00000333 ddd: 0x00000444"|sed 's/.*ccc: \([^ ]*\).*/\1/g' 0x00000333

If you really want to use awk:

$ echo "aaa: 0x00000111 bbb: 0x00000222 ccc: 0x00000333 ddd: 0x00000444"|awk '/ccc:/{s=$0; gsub(".*ccc: ", "", s); gsub(" .*$", "", s); print s}' 0x00000333