从indexof（word）到下一行的子字符串(substring from indexof(word) until next line)

从indexof（word）到下一行的子字符串(substring from indexof(word) until next line)

我想从indexof("&")直到下一行的subString，我的代码是

String substring = thisSrch.srchdesc.substring(thisSrch.srchdesc.indexOf("&"), frstNextNewLine);

但我不知道我怎么能找到frstNextNewLine为frstNextNewLine我想检测“ ＆Ali是加入的第一个人。 ”在下面的文字

一个美妙的宁静占据了我的整个灵魂，就像我春天的甜蜜的早晨，我全心全意地享受。

＆Ali是第一个加入的人。

我独自一人，在这个地方感受到存在的魅力，这是为了像我一样的灵魂所创造的。

i want subString from indexof("&") until next line,my code is

String substring = thisSrch.srchdesc.substring(thisSrch.srchdesc.indexOf("&"), frstNextNewLine);

but i dont know how i can find frstNextNewLine for exmaple i want detect "& Ali is First person that joined." in below text

A wonderful serenity has taken possession of my entire soul, like these sweet mornings of spring which I enjoy with my whole heart.

& Ali is First person that joined.

I am alone, and feel the charm of existence in this spot, which was created for the bliss of souls like mine.

最满意答案

int andIndex = thisSrch.srchdesc.indexOf("&"); String substring = thisSrch.srchdesc.substring(andIndex, thisSrch.srchdesc.indexOf("\n", andIndex));

上面使用的indexOf函数接受一个参数，以开始在'＆'字符的索引之后查找新行。

int andIndex = thisSrch.srchdesc.indexOf("&"); String substring = thisSrch.srchdesc.substring(andIndex, thisSrch.srchdesc.indexOf("\n", andIndex));

The indexOf function used above accepts a parameter to starting looking for new line after the index of the '&' character.