如何从java脚本模板传递php参数

本文介绍了如何从java脚本模板传递php参数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我在下面有一个代码，通过从上传图片的文件夹中读取图片名称来显示图片名称。

I have a code below, which display image name on UI by reading it from the folder where those images are uploaded,

这些图片名称使用 java脚本模板，我想将该名称传递给php函数，以检查其状态

These image names are displaying using a java-script template, I want to pass that name to a php function in order to check its status by hitting the db by the image name..

以下是图片名称在UI中的显示方式：

Here is how the image name is displaying in UI:

<!-- The template to display files available for download --> <script id="template-download" type="text/x-tmpl"> {% for (var i=0, file; file=o.files[i]; i++) { %} <tr class="template-download fade"> <td> <span>{%=file.name%}</span> <!----- new update --------> var a= file.name; $.ajax({ type: "POST", url: "localhost/tripvioapp/trips/showStatus/", dataType: "text", data: {image_name: a,trip_id: '2'}, success: function(msg){ alert(msg);//how can i display this value in this place } }); </td> </tr> {% } %} </script>

基本上，我已经集成了使用Codeigniter进行文件上传（php框架）从本教程

Basically, i have integrated file upload with Codeigniter(php framework) From this tutorial

到目前为止我尝试了

{％= file.name％} 如下

$this->tripmodel->getImageStatusByUidName('\"{%=file.title%}\"',"2"); //calling php function

结果：

预期（因为它应该工作）

$this->tripmodel->getImageStatusByUidName("imageName.jpg","2");

任何人都可以帮我解决这个问题吗？

Can anyone help me with this,please?

推荐答案

你应该把php代码放在之类的

you should put php code betwee somthing like

<?php $this->tripmodel->getImageStatusByUidName( "{%=file.name%}","2"); ?>

使用它。我没有测试它