如何获得以下格式化输出?

本文介绍了如何获得以下格式化输出?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我编写代码以获得以下格式化输出，但是当我输入两位数的行数时，输出格式会发生变化.为什么?我该如何解决这个问题?

I wrote the code to get the following formatted output, but when I enter number of rows in double digits, the output format changes. Why? How can I fix this?

1 1 2 1 1 2 3 2 1 1 2 3 4 3 2 1

这是我的代码:

import java.util.*; class PTri { public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.println("Enter the no. of rows for which " + "triangle has to be constructed"); int numrow = sc.nextInt(); for (int i = 1; i <= numrow; i++) { for (int j = 1; j <= numrow - i; j++) { System.out.print(" "); } for (int k = 1; k < i * 2; k++) { System.out.print(Math.min(k, i * 2 - k) + " "); } System.out.println(); } } }

推荐答案

这是因为两位数的值会改变整个架构.集合会向右移动一个位置.所以你可以提出这样的条件.我在数字之间添加了一个额外的空格以提高可见性.

It's because the value in double digit will change the whole architecture.The set will shift to right one place. So you can put a condition like this. I have added one extra space between numbers to improve visibility.

import java.util.*; class PTri { public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.println("Enter the no. of rows for which " + "triangle has to be constructed"); int numrow = sc.nextInt(); for (int i = 1; i <= numrow; i++) { for (int j = 1; j <= (numrow - i); j++) { System.out.print(" "); } for (int k = 1; k < i * 2; k++) { int temp = Math.min(k, i * 2 - k); if (temp > 9) { System.out.print(temp + " "); } else { System.out.print(temp + " "); } } System.out.println(); } } }