搜索包含数组python中的字符串(search contains string in array python)

搜索包含数组python中的字符串(search contains string in array python)

我有这样一个字符串search = 'hello' ，我需要检查所有数组，看看是否有包含hello 。 例如：

"hello" == "123hello123" | true "hello" == "aasdasdasd123hello123" | true "hello" == "123123hello" | true

我需要搜索我的代码

list_all_files_in_google_drive - 它是我的所有文件名数组

filename - 名称文件，需要检查是否存在谷歌驱动器或不

if not any(file['title'] == filename for file in list_all_files_in_google_drive): print('file not exist')

我的代码不起作用，因为它的工作原理是这样的：

"hello" == "123hello123" | false "hello" == "aasdasdasd123hello123" | false "hello" == "123123hello" | false "hello" == "hello" | true

我需要它这样工作：

"hello" == "123hello123" | true "hello" == "aasdasdasd123hello123" | true "hello" == "123123hello" | true "hello" == "hello" | true

UPD：

我检查了运营商，它不输出true

filename = 'hello' list = ['123hello123', 'aasdasdasd123hello123', '123123hello'] if filename in list: print('true')

I have a string like this search = 'hello' and I need check all array to see if any contains hello. For example:

"hello" == "123hello123" | true "hello" == "aasdasdasd123hello123" | true "hello" == "123123hello" | true

I need something like search for my code

list_all_files_in_google_drive - it my all file name array

filename - name file, which need to check if exist in google drive or not

if not any(file['title'] == filename for file in list_all_files_in_google_drive): print('file not exist')

my code doesn't work because it works like this:

"hello" == "123hello123" | false "hello" == "aasdasdasd123hello123" | false "hello" == "123123hello" | false "hello" == "hello" | true

and I need it to work like this:

"hello" == "123hello123" | true "hello" == "aasdasdasd123hello123" | true "hello" == "123123hello" | true "hello" == "hello" | true

UPD:

I checked operator in and it does not output true

filename = 'hello' list = ['123hello123', 'aasdasdasd123hello123', '123123hello'] if filename in list: print('true')

最满意答案

只需用一个简单的循环遍历列表中的每个字符串，然后检查运算符中的pythons成员是否存在'hello' ：

lst = ['123hello123', 'aasdasdasd123hello123', '123123hello'] for x in lst: if 'hello' in x: print('true')

哪些输出：

true true true

或者如果你想一次查看all()字符串：

if all('hello' in x for x in lst): print('true')

或者，如果你想一次检查是否有any()的字符串：

if any('hello' in x for x in lst): print('true')

两者都会输出：

true

注意：在你的问题中使用list作为变量名不是一个好主意，因为它会影响内置函数list() 。 在这里返回一个布尔值True或False是好的，不需要返回这些字符串形式。

Just go through each string in the list with a simple loop, and check if 'hello' exists with the pythons membership in operator:

lst = ['123hello123', 'aasdasdasd123hello123', '123123hello'] for x in lst: if 'hello' in x: print('true')

Which outputs:

true true true

Or if you want to check all() the strings in lst at once:

if all('hello' in x for x in lst): print('true')

Or if you want to check if any() of the strings in lst at once:

if any('hello' in x for x in lst): print('true')

Both of which will output:

true

Note: Using list as a variable name as shown in your question is not a good idea here, as it shadows the builtin function list(). Also returning a boolean True or False here is fine, not need to return a string form of these.