如何在java中打印'％'符号[重复](How to print a '%' sign in java [duplicate])

如何在java中打印'％'符号[重复](How to print a '%' sign in java [duplicate])

这个问题在这里已有答案：

Java：文字百分号签到printf语句 3答案

我最近一直在尝试java，但我现在遇到了这个问题：

我不知道如何在java中打印'％'符号。

如果有人可以提供帮助，请做！

这是我的代码：

import java.util.Scanner; class Averager { public static void main(String args[]) { //A Simple Averaging Program Scanner input = new Scanner(System.in); //Declare variables: double total = 0; double counter = 0; long mark; double average; int numOfPupils; int totalMarks; //Ask how many papers the teacher would like to average: System.out.println("How many student's papers would you like to avarage?"); numOfPupils = input.nextInt(); //Ask how many marks were available to the student to earn: System.out.println("How many marks were available to the student?"); totalMarks = input.nextInt(); //Repeat the amount of papers times: while (counter < numOfPupils) { //Ask how many marks the student got: System.out.printf("How many marks did student number %s get? \nStudent %s scored: ", counter + 1, counter + 1); mark = input.nextLong(); total += mark; System.out.printf("Student %s scored: %s %", counter + 1, ((100 / totalMarks) * mark)); counter++; } average = total / (counter); System.out.printf("The average was %s marks.", average); input.close(); } }

...它说我的帖子主要是代码，所以我会在这里添加更多细节。

我正在使用eclips Mars 1

我大约3天前开始使用java - 一位朋友教我如何使用它。

提前谢谢了，

Sheikh1365

This question already has an answer here:

Java: Literal percent sign in printf statement 3 answers

How do I print a % sign in Java? I have tried "\%", which doesn't seem to work. Any ideas?

最满意答案

贝娄是纠正的代码，如上所述你应该使用双％来逃避％，即： %%

我还添加了一些新的行字符，使应用程序看起来更整洁。

import java.util.Scanner; public class test { public static void main(String args[]) { //A Simple Averaging Program Scanner input = new Scanner(System.in); //Declare variables: double total = 0; double counter = 0; long mark; double average; int numOfPupils; int totalMarks; //Ask how many papers the teacher would like to average: System.out.println("How many student's papers would you like to avarage?"); numOfPupils = input.nextInt(); //Ask how many marks were available to the student to earn: System.out.println("How many marks were available to the student?"); totalMarks = input.nextInt(); //Repeat the amount of papers times: while (counter < numOfPupils) { //Ask how many marks the student got: System.out.printf("\nHow many marks did student number %s get? \nStudent %s scored: ", counter + 1, counter + 1); mark = input.nextLong(); total += mark; System.out.printf("Student %s scored: %s%%", counter + 1, ((100 / totalMarks) * mark)); counter++; } average = total / (counter); System.out.printf("\nThe average was %s marks.", average); input.close(); } }

偏离主题但可能需要考虑的是，在某些情况下，您的代码会失败，因为您需要处理一些无效输入。

Bellow is the code corrected, as mentioned above you should use double % to escape %, i.e: %%

I have also added some new line characters to make the app look more neat.

import java.util.Scanner; public class test { public static void main(String args[]) { //A Simple Averaging Program Scanner input = new Scanner(System.in); //Declare variables: double total = 0; double counter = 0; long mark; double average; int numOfPupils; int totalMarks; //Ask how many papers the teacher would like to average: System.out.println("How many student's papers would you like to avarage?"); numOfPupils = input.nextInt(); //Ask how many marks were available to the student to earn: System.out.println("How many marks were available to the student?"); totalMarks = input.nextInt(); //Repeat the amount of papers times: while (counter < numOfPupils) { //Ask how many marks the student got: System.out.printf("\nHow many marks did student number %s get? \nStudent %s scored: ", counter + 1, counter + 1); mark = input.nextLong(); total += mark; System.out.printf("Student %s scored: %s%%", counter + 1, ((100 / totalMarks) * mark)); counter++; } average = total / (counter); System.out.printf("\nThe average was %s marks.", average); input.close(); } }

Off-topic but may need consideration, is that your code will fail in some cases, as you need to handle some invalid inputs.