程序要求输入，然后不显示任何输出。

本文介绍了程序要求输入，然后不显示任何输出。的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

#include<stdio.h> main() { int scores[3], sum; float avg; printf("enter the value for scores\n"); scanf("%d\n %d\n %d\n",&scores[0],&scores[1],&scores[2]); sum=scores[0]+scores[1]+scores[2]; avg=sum/3; printf("The sum is :%d\n The avg is :%f\n",sum,avg); system("pause"); }

真正的计划是：

The real program is:

#include<stdio.h> main() { int scores[3],sum; float avg; printf("Enter Score 1 : "); scanf("%d",&scores[0]); printf("Enter Score 2 : "); scanf("%d",&scores[1]); printf("Enter Score 3 : "); scanf("%d",&scores[2]); sum=scores[0]+scores[1]+scores[2]; avg=sum/3; printf("Sum is = %d\nAverage = %f\n",sum,avg); system("pause");

我尝试过： 问题很大，我试图修剪它但输入3个输入时没有显示输出。

What I have tried: The problem is big and I tried to trim it but it is showing no output when I enter 3 inputs.

推荐答案

它适用于我： It works fine for me: enter the value for scores 10 20 30 The sum is :60 The avg is :20 Sum is = 60 Average = 20

并且

Enter Score 1 : 10 Enter Score 2 : 20 Enter Score 3 : 30 Sum is = 60 Average = 20

检查您是否正在运行正确的可执行文件...并尝试摆脱系统（暂停）行。

#include<stdio.h> int main(void) { int scores[3], sum; float avg; printf("enter the value for scores\n"); scanf("%d%d%d",&scores[0],&scores[1],&scores[2]); sum=scores[0]+scores[1]+scores[2]; avg=sum/3.0; printf("The sum is :%d\n The avg is :%f\n",sum,avg); return 0; }