本文介绍了程序要求输入,然后不显示任何输出。的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
#include<stdio.h> main() { int scores[3], sum; float avg; printf("enter the value for scores\n"); scanf("%d\n %d\n %d\n",&scores[0],&scores[1],&scores[2]); sum=scores[0]+scores[1]+scores[2]; avg=sum/3; printf("The sum is :%d\n The avg is :%f\n",sum,avg); system("pause"); }
真正的计划是:
The real program is:
#include<stdio.h> main() { int scores[3],sum; float avg; printf("Enter Score 1 : "); scanf("%d",&scores[0]); printf("Enter Score 2 : "); scanf("%d",&scores[1]); printf("Enter Score 3 : "); scanf("%d",&scores[2]); sum=scores[0]+scores[1]+scores[2]; avg=sum/3; printf("Sum is = %d\nAverage = %f\n",sum,avg); system("pause");我尝试过: 问题很大,我试图修剪它但输入3个输入时没有显示输出。
What I have tried: The problem is big and I tried to trim it but it is showing no output when I enter 3 inputs.
推荐答案它适用于我: It works fine for me: enter the value for scores 10 20 30 The sum is :60 The avg is :20 Sum is = 60 Average = 20
并且
Enter Score 1 : 10 Enter Score 2 : 20 Enter Score 3 : 30 Sum is = 60 Average = 20检查您是否正在运行正确的可执行文件...并尝试摆脱系统(暂停)行。
#include<stdio.h> int main(void) { int scores[3], sum; float avg; printf("enter the value for scores\n"); scanf("%d%d%d",&scores[0],&scores[1],&scores[2]); sum=scores[0]+scores[1]+scores[2]; avg=sum/3.0; printf("The sum is :%d\n The avg is :%f\n",sum,avg); return 0; }
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程序要求输入,然后不显示任何输出。
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