使用PHP进行OS检测的最简单方法?

本文介绍了使用PHP进行OS检测的最简单方法?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我试图确定访客的操作系统是使用PHP的Windows，Mac还是Linux(我不需要版本，发行信息等).有几种方法，但是对于这个简单的要求，它们看起来太复杂了.

I'm trying to figure out the visitor's OS is either a Windows, Mac or Linux using PHP(I don't need the version, distro info.. etc). There's several methods out there however they look a bit too complicated for this simple requirement.

是否有任何简单的方法可以提供这类信息，但仍然相当可靠?

Are there any simple ways that could provide this sort of information yet still being quite reliable?

谢谢.

推荐答案

为简单的解决方案，请查看这里. 用户代理标头可能会显示一些操作系统信息，但我不会指望这一点.

For an easy solution have a look here. The user-agent header might reveal some OS information, but i wouldn't count on that.

对于您的用例，我将使用客户端的javascript进行ajax调用，以将客户端操作系统通知您的服务器.并做到防水.

For your use case i would do an ajax call using javascript from the client side to inform your server of the client's OS. And do it waterproof.

这里是一个例子.

Javascript(客户端，浏览器检测+ ajax调用):

Javascript (client side, browser detection + ajax call ):

window.addEvent('domready', function() { if (BrowserDetect) { var q_data = 'ajax=true&browser=' + BrowserDetect.browser + '&version=' + BrowserDetect.version + '&os=' + BrowserDetect.OS; var query = 'record_browser.php' var req = new Request.JSON({url: query, onComplete: setSelectWithJSON, data: q_data}).post(); } });

PHP(服务器端):

PHP (server side):

if ($_SERVER['REQUEST_METHOD'] == 'POST') { $session = session_id(); $user_id = isset($user_id) ? $user_id : 0; $browser = isset($_POST['browser']) ? $_POST['browser'] : ''; $version = isset($_POST['version']) ? $_POST['version'] : ''; $os = isset($_POST['os']) ? $_POST['os'] : ''; // now do here whatever you like with this information }