使用PHPUnit模拟Symfony2中的SecurityContext(Mocking SecurityContext in Symfony2 using PHPUnit)

编程入门 行业动态 更新时间:2024-10-28 17:23:11
使用PHPUnit模拟Symfony2中的SecurityContext(Mocking SecurityContext in Symfony2 using PHPUnit)

这些是我的嘲笑:

$this->user->method('getCustomerId') ->willReturn($this->customerId); $this->userToken->method('getUser') ->willReturn($this->user); $this->securityContext->method('getToken') ->willReturn($this->userToken); $this->securityContext->expects($this->once()) ->method('isGranted') ->will($this->returnValue(true));

这是我正在测试的类的代码:

$token = $securityContext->getToken(); $isFullyAuthenticated = $securityContext->isGranted('IS_AUTHENTICATED_FULLY');

它抛出错误:

Symfony\Component\Security\Core\Exception\AuthenticationCredentialsNotFoundException: The security context contains no authentication token. One possible reason may be that there is no firewall configured for this URL.

我不知道现在该做什么,我虽然嘲笑了方法调用并返回了我想要的任何东西。 但在这种情况下,似乎是格兰特方法不是模拟

These are my mocks:

$this->user->method('getCustomerId') ->willReturn($this->customerId); $this->userToken->method('getUser') ->willReturn($this->user); $this->securityContext->method('getToken') ->willReturn($this->userToken); $this->securityContext->expects($this->once()) ->method('isGranted') ->will($this->returnValue(true));

And this is the code of the class I am testing:

$token = $securityContext->getToken(); $isFullyAuthenticated = $securityContext->isGranted('IS_AUTHENTICATED_FULLY');

It throws the error:

Symfony\Component\Security\Core\Exception\AuthenticationCredentialsNotFoundException: The security context contains no authentication token. One possible reason may be that there is no firewall configured for this URL.

I have no idea what to do at this point, I though mocks intercepted the call to methods and returned whatever I wanted. But in this case is seems the isGranted methods is not being mock

最满意答案

尝试使用willReturn而不是will并添加with

所以试试这个:

$this->securityContext->expects($this->once()) ->method('isGranted') ->with('IS_AUTHENTICATED_FULLY') ->willReturn(true);

取而代之的是:

$this->securityContext->expects($this->once()) ->method('isGranted') ->will($this->returnValue(true));

希望这个帮助

I figured out that the problem is that the isGranted method is final, so it's imposible to mock, the workaround the problem was to mock all the attributes of SecurityContext so that when the method is call it returns my desired output, instead of intercepting the call with a mock method.

更多推荐

本文发布于:2023-07-05 00:57:00,感谢您对本站的认可!
本文链接:https://www.elefans.com/category/jswz/34/1031210.html
版权声明:本站内容均来自互联网,仅供演示用,请勿用于商业和其他非法用途。如果侵犯了您的权益请与我们联系,我们将在24小时内删除。
本文标签:PHPUnit   Mocking   SecurityContext

发布评论

评论列表 (有 0 条评论)
草根站长

>www.elefans.com

编程频道|电子爱好者 - 技术资讯及电子产品介绍!