如何从角度为 6 的数组中删除重复的对象

本文介绍了如何从角度为 6 的数组中删除重复的对象的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

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我正在尝试删除数组中的重复值对象但不起作用...我认为重复函数正在运行但未反映在 li 列表中.你能找出我必须改变的地方吗?

I am trying to remove duplicate value objects in an array but not working... I think duplicate function is working but not reflecting in li list. Can you find out where I have to change?

我的服务文件:

 addComp(Names,c){   
 this.item.push({ name: Names, componentid: c});
 this.uniqueArray = this.removeDuplicates(this.item, "name"); //this line issue
 this.item=this.uniqueArray; //this line issue
 }

推荐答案

如果 addComp 是您修改 this.item 的唯一地方，只需在插入前检查是否存在.重复项永远不会放入数组中，因此您永远不必修剪它们.

If addComp is the only place you modify this.item, just check for existing prior to insertion. Duplicates will never get put in the array, so you'll never have to trim them.

addComp(Names,c){
  let item = {name: Names, componentid: c};
  if (this.item.find((test) => test.name === Names) === undefined) {
    this.item.push(item);
  }
}

或者，如果您正在修改this.item 的其他地方，您应该在更预期的地方去除重复项.作为 addComp 函数的副作用将它们剥离是出乎意料的.但是，你可以做到...

Alternatively, if there are other places that you're modifying this.item, you should be stripping duplicates in a more expected place. Stripping them as a side-effect of the addComp function is unexpected. However, you could do it...

addComp(Names,c){
  this.item.push({name: Names, componentid: c});
  this.item = this.item.filter((test, index, array) =>
     index === array.findIndex((findTest) =>
        findTest.name === test.name
     )
  );
}

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