如果我有这个:
case class Foo( age: Int, name: String, bar: List[Bar], alive: Boolean ) case class Bar( hey: String, you: String )我可以创建一个可以获取/设置foo.bar(1).you的镜头吗?
If I have this:
case class Foo( age: Int, name: String, bar: List[Bar], alive: Boolean ) case class Bar( hey: String, you: String )Can I create a lens that can get/set foo.bar(1).you?
最满意答案
不是开箱即用,而且您确实需要一个部分镜头,以负责任的方式通过索引在列表中进行查找。 尽管如此,Scalaz提供了您所需要的功能,而无形化contrib使互操作性变得轻松:
import scalaz.PLens._ import shapeless.lens import shapeless.contrib.scalaz._ val secondBar = (lens[Foo] >> 'bar).asScalaz.partial.andThen(listNthPLens(1))接着:
scala> secondBar.get(fooB) res0: Option[Bar] = None scala> secondBar.get(fooA) res1: Option[Bar] = Some(Bar(foo,bar)) scala> secondBar.set(fooA, Bar("bar", "foo")) res2: Option[Foo] = Some(Foo(1,,List(Bar(,), Bar(bar,foo)),false)) scala> secondBar.set(fooB, Bar("bar", "foo")) res3: Option[Foo] = None如果你不介意过着危险的生活,你也可以编写自己的无形镜头来查找列表中的位置(类型为Lens[List[A], A] ),但这会放弃很多无形和镜片的价值。
Not out of the box, and you really need a partial lens to look things up in a list by index responsibly. Scalaz provides what you need, though, and shapeless-contrib makes interoperability easy:
import scalaz.PLens._ import shapeless.lens import shapeless.contrib.scalaz._ val secondBar = (lens[Foo] >> 'bar).asScalaz.partial.andThen(listNthPLens(1))And then:
scala> secondBar.get(fooB) res0: Option[Bar] = None scala> secondBar.get(fooA) res1: Option[Bar] = Some(Bar(foo,bar)) scala> secondBar.set(fooA, Bar("bar", "foo")) res2: Option[Foo] = Some(Foo(1,,List(Bar(,), Bar(bar,foo)),false)) scala> secondBar.set(fooB, Bar("bar", "foo")) res3: Option[Foo] = NoneIf you don't mind living dangerously, you could also write your own Shapeless lens for looking up locations in a list (with a type like Lens[List[A], A]), but that would be giving up a lot of the value of both Shapeless and lenses.
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