我正在尝试在as3中搜索此XML文档
<mineral> <name>Calcite</name> <color>White</color <diaphaneity>Opaque</diaphaneity> </mineral> <mineral> <name>Spangolite</name> <color>Blue</color> <color>Green</color> <color>Blue Green</color> <color>Dark Green</color> <color>Emerald Green</color> <diaphaneity>Transparent</diaphaneity> <diaphaneity>Translucent</diaphaneity> </mineral> <mineral> <name>Barite</name> <color>Yellow</color> <color>Honey</color> <diaphaneity>Transparent</diaphaneity> <diaphaneity>Translucent</diaphaneity> <diaphaneity>Opaque</diaphaneity> </mineral> <mineral> <name>Landauite</name> <color>White</color> <diaphaneity>Transparent</diaphaneity> <diaphaneity>Translucent</diaphaneity> </mineral> <mineral> <name>Sapphire</name> <color>Blue</color> <color>Blue green</color> <diaphaneity>Transparent</diaphaneity> <diaphaneity>Translucent</diaphaneity> </mineral>并首先按颜色过滤结果。 因此，如果您搜索“蓝色”，您将获得包含“颜色”元素的所有矿物的结果，其值为“蓝色”（Spangolite和Sapphire）。
我加载我的XML并创建所有元素的XMLList。
var dataLoader:URLLoader = new URLLoader(); var xmlData:XML; dataLoader.addEventListener(Event.COMPLETE, LoadComplete); dataLoader.load(new URLRequest("mineralXML.xml")); function LoadComplete(e:Event):void { xmlData = new XML(e.target.data); ParseMinerals(xmlData); } function ParseMinerals(mineralXML:XML):void { var mineralList:XMLList = mineralXML.mineral; trace(mineralList); }使用“trace（mineralList）”命令，它将成功跟踪整个XML文件，如果我将其更改为“trace（xmlData.mineral。（color ==”White“））;” 然后它会追踪一个值为“White”的元素的所有节点。
<mineral> <name>Calcite</name> <color>White</color> <diaphaneity>Opaque</diaphaneity> </mineral> <mineral> <name>Landauite</name> <color>White</color> <diaphaneity>Transparent</diaphaneity> <diaphaneity>Translucent</diaphaneity> </mineral>但是，如果我搜索蓝色而不是白色，它不会追踪任何东西。 我猜这是因为包含值为“Blue”的元素的矿物节点也有多个其他颜色值。 这是我想要评估的问题。
我需要能够搜索颜色并拉出具有这些颜色值之一的所有节点，而不管其他颜色值。
I'm trying to search this XML document in as3
<mineral> <name>Calcite</name> <color>White</color <diaphaneity>Opaque</diaphaneity> </mineral> <mineral> <name>Spangolite</name> <color>Blue</color> <color>Green</color> <color>Blue Green</color> <color>Dark Green</color> <color>Emerald Green</color> <diaphaneity>Transparent</diaphaneity> <diaphaneity>Translucent</diaphaneity> </mineral> <mineral> <name>Barite</name> <color>Yellow</color> <color>Honey</color> <diaphaneity>Transparent</diaphaneity> <diaphaneity>Translucent</diaphaneity> <diaphaneity>Opaque</diaphaneity> </mineral> <mineral> <name>Landauite</name> <color>White</color> <diaphaneity>Transparent</diaphaneity> <diaphaneity>Translucent</diaphaneity> </mineral> <mineral> <name>Sapphire</name> <color>Blue</color> <color>Blue green</color> <diaphaneity>Transparent</diaphaneity> <diaphaneity>Translucent</diaphaneity> </mineral>and filter the results by Color first. So if you search for "Blue" you will get results of all the minerals that contain a "color" element who's value is "Blue" (Spangolite and Sapphire).
I load in my XML and create an XMLList of all the elements.
var dataLoader:URLLoader = new URLLoader(); var xmlData:XML; dataLoader.addEventListener(Event.COMPLETE, LoadComplete); dataLoader.load(new URLRequest("mineralXML.xml")); function LoadComplete(e:Event):void { xmlData = new XML(e.target.data); ParseMinerals(xmlData); } function ParseMinerals(mineralXML:XML):void { var mineralList:XMLList = mineralXML.mineral; trace(mineralList); }With the "trace(mineralList)" command it will successfully trace the entire XML file, and if I change it to "trace(xmlData.mineral.(color == "White"));" then it traces out all of the nodes that a element with the value of "White".
<mineral> <name>Calcite</name> <color>White</color> <diaphaneity>Opaque</diaphaneity> </mineral> <mineral> <name>Landauite</name> <color>White</color> <diaphaneity>Transparent</diaphaneity> <diaphaneity>Translucent</diaphaneity> </mineral>However, if I search for Blue instead of White, it doesn't trace out anything. I'm guessing this is because the mineral nodes containing a element with values of "Blue" also have multiple other color values. This is the problem I am trying to assess.
I need to be able to search for a color and pull out all of the nodes that have one of those color values, regardless of having other color values.
最满意答案
在您的代码中，节点在color == white的情况下只有一个节点。 在其他情况下，它有多个节点。 所以尝试这样，
private function ParseMinerals(mineralXML:XML):void { var mineralList:XMLList = mineralXML.mineral; for each (var mineral:XML in mineralList) { if(mineral.color.length()>1) { for each(var color in mineral.color) { if(color == "Green") { trace(mineral); } } } else { if(mineral.color == "White") { trace(mineral); } } }I actually achieved this with the following code:
first I made an array for the results to be contained in when they are defined as well as a variable to note which result number the loop was at
var resultArray:Array = new Array; var resultNum:Number = 0;then I made a shared object out of the XML data
function ParseMinerals(mineralXML:XML):void { //create a var called memory and datatype it to SharedObject and name the //file "attributes" var memory:SharedObject = SharedObject.getLocal("attributes"); //create an XMLList containing the information in mineralXML.mineral var mineralList:XMLList = mineralXML.mineral; //save the data in mineralList to shared object memory.data.mineralList = mineralList; memory.flush(); }instead of running the code after the xml was loaded in the ParseMinerals function, I put it in a new function called "search" which runs when you push the "search" button.
function search(event:MouseEvent):void { //load shared file var memory:SharedObject = SharedObject.getLocal("attributes"); //create a variable that is the length of the list of minerals var len:int = memory.data.mineralList.length(); //create variables to temporarily store information regarding minerals color //and name var thisColor:String; var thisName:String; //create var that increments for each time you loop through a "mineral" node for (var i:int = 0; i < len; i++) { //create var that increments for each time you loop through a "color" //element within a single "mineral" node for (var c:int = 0; c < xmlData.mineral[i].color.length(); c++) { //make thisColor equal to the current color that the for loop is on thisColor = xmlData.mineral[i].color[c]; //make thisName equal to the current name that the for loop is on thisName = xmlData.mineral[i].name; //if the color that the for loop is currently on is equal to the //color you are searching for... if (thisColor == memory.data.mineralColor){ //... then put the name of that mineral into an array resultArray.push(thisName); //... add 1 to the current result number resultNum ++; //... and trace the current result number and the name of the //... mineral corresponding to the color you are searching for trace("Result #" + resultNum + ": " + (thisName)); } } } //reset array resultArray.length = 0; //reset result number resultNum = 0; }I'm not sure if this is the most efficient way to achieve the goal, but it works. If I select "White" from the list and click the Search button I made, the program traces
Result #1: Calcite Calciteand if I search for "Blue" then the program traces
Result #1: Spangolite Result #2: Sapphire Spangolite, SapphireI hope this helps anybody that is trying to achieve a similar goal.
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