将数字字符串转换为整数列表[重复](Converting String of digits to List of integer [duplicate])

将数字字符串转换为整数列表[重复](Converting String of digits to List of integer [duplicate])

这个问题在这里已有答案：

如何将Java 8 IntStream转换为List？ 3个答案

我正在做一些关于java 8流功能的练习，所以想到应用知识的问题将数字字符串转换为整数列表

典型的测试看起来像

@Test public void testGetListofIntegersFromString(){ List<Integer> result = getIntegers("123456780"); assertEquals(Arrays.asList(1,2,3,4,5,6,7,8,0),result); }

我写了下面的方法

List<Integer> getIntegers(String value) { return IntStream.rangeClosed(0, value.length() - 1).map(i -> Integer.valueOf(value.substring(i,i+1))).collect(?????); }

我被困在哪个函数用于获取我尝试collect(Collectors.toList())的整数列表collect(Collectors.toList())它给出编译错误。

请建议我们是否可以遵循不同的解决方案。

This question already has an answer here:

How do I convert a Java 8 IntStream to a List? 4 answers

I am doing some hands on exercise on java 8 stream features so thought of applying the knowledge with the problem Converting String of digits to List of integer

a typical test would look like

@Test public void testGetListofIntegersFromString(){ List<Integer> result = getIntegers("123456780"); assertEquals(Arrays.asList(1,2,3,4,5,6,7,8,0),result); }

I have written below method

List<Integer> getIntegers(String value) { return IntStream.rangeClosed(0, value.length() - 1).map(i -> Integer.valueOf(value.substring(i,i+1))).collect(?????); }

I am stuck about which function to use to get The List Of Integers I tried collect(Collectors.toList()) Its giving compilation error.

Please suggest if we can follow different to solve this .

最满意答案

使用String.chars（）：

"123456780".chars().map(c -> c-'0').boxed().collect(Collectors.toList());

Use String.chars():

"123456780".chars().map(c -> c-'0').boxed().collect(Collectors.toList());