使用函数来排序奇数和偶数Javascript(using a function to sort odd and even numbers Javascript)
大家好我正在尝试对数组的奇数和偶数进行排序,然后将每个数据的总数显示在我的网页上。 我运行代码时没有得到任何响应。 谁能告诉我他们是否看错了我不知道? 提前谢谢。 var numList = [1,2,3,4,5,6,7,8,9,10];
function numberTally(numList){ var evenTotal = 0; var oddTotal = 0; for (var i = 0; i < numList.length; i++) { if (i % 2) { // i is odd oddTotal += numList[i]; // or oddTotal = oddTotal + numList[i]; } else (i % 3){ // i is even evenTotal += numList[i]; } } alert(oddTotal); return evenTotal; }Hi everyone I am trying to make a function to sort the odd and even numbers of an array and then display the total of each to my webpage. I don't get any response when I run my code. Could anyone tell me if they see something wrong I don't? Thanks ahead of time. var numList = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
function numberTally(numList){ var evenTotal = 0; var oddTotal = 0; for (var i = 0; i < numList.length; i++) { if (i % 2) { // i is odd oddTotal += numList[i]; // or oddTotal = oddTotal + numList[i]; } else (i % 3){ // i is even evenTotal += numList[i]; } } alert(oddTotal); return evenTotal; }最满意答案
尝试这个:
function numberTally(numList){ var evenTotal = 0; var oddTotal = 0; for (var i = 0; i < numList.length; i++) { if (i % 2) { // i is odd oddTotal += numList[i]; } else { // i is even evenTotal += numList[i]; } } alert(oddTotal); return evenTotal; }Try this:
function numberTally(numList){ var evenTotal = 0; var oddTotal = 0; for (var i = 0; i < numList.length; i++) { if (i % 2) { // i is odd oddTotal += numList[i]; } else { // i is even evenTotal += numList[i]; } } alert(oddTotal); return evenTotal; }更多推荐
发布评论