如何返回不在Javascript地图中的元素数组？(How do I return an array of elements NOT in a Javascript map?)

如何返回不在Javascript地图中的元素数组？(How do I return an array of elements NOT in a Javascript map?)

我有一个Javascript对象：

var errorMap = { 100: 'You must enter a name.', 200: 'You must enter an address.', 300: 'You must enter a DOB.' }

在我的代码的另一部分，我收到一组错误代码：

var errorCodes = [100, 200, 500, 600];

我想要做的是将errorCodes数组与errorMap对象的键进行比较，并返回errorMap 没有相应键的所有错误代码。 在这种情况下，我想得到这个：

[500, 600]

我该怎么做呢？ 我可以访问jQuery。

I have a Javascript object:

var errorMap = { 100: 'You must enter a name.', 200: 'You must enter an address.', 300: 'You must enter a DOB.' }

In another part of my code, I am receiving an array of error codes:

var errorCodes = [100, 200, 500, 600];

What I'd like to do is compare the errorCodes array to the errorMap object's keys and return all error codes that do not have a corresponding key in errorMap. In this case, I would like to get this back:

[500, 600]

How do I do this? I have access to jQuery.

最满意答案

适用于现代浏览器的Javascript（适用于带有填充程序的旧版浏览器）

var missing = [100, 200, 500, 600].filter(function(v){ return !errorMap.hasOwnProperty(v) }); //missing = [500, 600]

jQuery，以防需要遗留浏览器支持，并且不接受填充：

var missing = $.grep( [100, 200, 500, 600], function(v){ return !errorMap.hasOwnProperty(v) }); //missing = [500, 600]

Javascript for modern browsers (works in older browsers with a shim)

var missing = [100, 200, 500, 600].filter(function(v){ return !errorMap.hasOwnProperty(v) }); //missing = [500, 600]

jQuery in case legacy browser support is required and shim is not acceptable:

var missing = $.grep( [100, 200, 500, 600], function(v){ return !errorMap.hasOwnProperty(v) }); //missing = [500, 600]