使用相同参数时爆炸是否等同于内爆？(Is explode equivalent to implode when using the same parameter?)

使用相同参数时爆炸是否等同于内爆？(Is explode equivalent to implode when using the same parameter?)

假设我有以下功能：

public function normalize($string) { $substrings = explode(",", $string); return implode(",", $substrings); }

Will ($string == normalize($string))总是如此？ 有什么特别的情况我应该考虑吗？

Let's say I have the following function:

public function normalize($string) { $substrings = explode(",", $string); return implode(",", $substrings); }

Will ($string == normalize($string)) always be true? is there any special case I should consider?

最满意答案

如果$ string是一个字符串，是的。

否则可能会发生类型转换：

implode(",", explode(",", 0))

这将导致“0”因此$string !== normalize($string)但$string == normalize($string)仍然成立。

If $string is a string, yes.

Otherwise type conversion may occur:

implode(",", explode(",", 0))

This will result in "0" thus $string !== normalize($string) but $string == normalize($string) still holds true.